Answer:
Simply, it's just the velocity at a given moment in time.
Explanation:
Instantaneous velocity is basically just short for the velocity of something at any given time. To give an example, let's say I wind up a toy car and set him to go forward for 10 seconds, and 5 seconds in, I freeze time. The speed of the car at that moment is the instantaneous velocity.
Four charges of equal magnitude, q = +1 uC, are placed at the four corners of a square with a side length of 1 meter located in the xy-plane. A small ball with a known charge +2 uC and an unknown mass is placed 2 meters above the center of the square (so along the z-axis).
Required:
a. What is the total force on the small ball from the four charges?
b. If the ball is in equilibrium where it was placed and we assume standard earth gravity, 9.8 m/s^2, what must the mass of the ball be?
Answer:
a) F _total = 15.08 10⁻³ N , b) m = 1,539 10⁻³ kg
Explanation:
a) To solve this problem we can use Coulomb's law to find the force created by each charge
F =[tex]k \frac{\ q_{1} q_{2} }{r_{12}^{2} }[/tex]
and the total force is
F = F₁₅ + F₂₅ + F₃₅ + F₄₅
The bold are vectros, In the exercise they indicate the charges
q₁ = q₂= q₃ = q₄ = 1 10⁻⁶ C
q₅ = 2 10⁻⁶ C
Let's set a reference system where the sphere is on the z axis and the other charges on the xy plane, let's write the coordinates of card charge
sphere (subscript 5)
x₅ = 0
y₅ = 0
z₅ = 2 m
charge 1
x = 0.5 m
y = 0.5 m
z = 0
charge 2
x = -0.5 m
y = 0.5 m
z = 0
charge 3
x = -0.5 m
y = -0.5 m
z = 0
charge 4
x = 0.5 m
y = -0.5 m
z = 0
With these values we can calculate the distance between each charge and the sphere
charge 1 and sphere
r₁₅² = (x₅ -x₁)² + (y₅ - y₁)² + (z₅ -z₁)²
substitute
r₁₅² = (0- 0.5)² + (0 - 0.5)² + (2 -0)²
r₁₅² = 0.5² + 0.5² + 2²
r₁₅² = 4.5
we can see that for the other charges the result is the same since being squared always gives positive
r₁₅ = r₂₅ = r₃₅ = r₄₅
the force created by the card charge on the sphere is the projection on the Z axis of the total force
Let's find the angle with respect to the Z axis
tan φ = r / z
where r is the magnitude of the vector in the xy plane
r = [tex]\sqrt{0.5^{2} + 0.5^{2} }[/tex]
r = 0.7071 m
φ = tan⁻¹ r / z
φ = tan⁻¹ (0.7071 / 2)
φ = 19.5
consequently the total force is
F_total = 4 F cos 19.5
F _total = [tex]4 \frac{k \ q_{1} q_{5} }{r_{15}^{2}}[/tex] cos 19.5
let's calculate
F_toal = 4 9 10⁹ 1 10⁻⁶ 2 10⁻⁶ /4.5 cos 19.5
F _total = 15.08 10⁻³ N
b) For this part indicate that the sphere is in equilibrium with the weight
F_total - W = 0
W = mg
F_total = mg
m = F_total / g
m = 15.08 10³ / 9.8
m = 1,539 10⁻³ kg
How can land that was formerly used as dumps, mines, or factory sites be.
rehabilitated?
Answer:
clear out the junk, and plant some stuff
Explanation:
clear out all of the nasties, unless it is biodegradable, or you could get some mushrooms to break everything down, then you can go and plant some stuff or do whatever. You could turn it into a playground, park, whatever.
Question 2 (10 points)
A football player kicks a ball with a mass of 0.5 kg. The average acceleration of the football was 15 m/s/s. How much force did the kicker apply to the football?
Question 2 options:
15.5 N
30 N
7.5 N
14.5 N
Answer:
7.5N
Explanation:
Given parameters:
Mass of the ball = 0.5kg
Acceleration = 15m/s²
Unknown:
Force exerted by the kicker = ?
Solution:
To know the force exerted by the kicker, we use the mathematical expression below:
Force = mass x acceleration
This is based on Newton's second law of motion;
Now insert the parameters and solve;
Force = 0.5 x 15 = 7.5N
I will give 20 points and brainliest
Space exploration can lead to money going to U.S.
businesses and universities.
What are two things NASA might hire U.S. businesses and universities to do?
A. Teach people to read
B. Research new ideas
C. Build complex equipment
D. Improve athletic teams
Answer:
b and c
Explanation:
NASA might hire U.S. businesses and universities to do: Research new ideas, build complex equipment. Hence, option (b) and (c) are correct.
What is Space exploration?Astronomy and space technology are used in space exploration to learn more about the universe. While astronomers use telescopes to explore the universe, both unmanned robotic space missions and human spaceflight also participate in the physical exploration of space. One of the main sources of space science, like its traditional form astronomy, is space exploration.
Although astronomy, or the study of celestial objects, has existed since the beginning of trustworthy written history, it wasn't until the mid-20th century that the possibility of physical space exploration became a reality.
Space exploration can lead to money going to U.S. businesses and universities. Hence, NASA might hire U.S. businesses and universities to do: Research new ideas, build complex equipment.
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A horizontal force of 90.7 N is applied to a 40.5 kg crate on a rough, level surface. If the crate accelerates at 1.08 m/s, what is the magnitude of the force of kinetic friction (in N) acting on the crate?
Need help ASAP please helppp
Answer:
2.3 newtons of force
Explanation:
Divide the weight by the speed of the bike
Q2) A Ferrari moves at 240 km/h for 1.2 h. How far it will go.
Answer:
Explanation:
Multiply the two numbers to get the distance. 240 x 1.2 = 288km
Please help me and thank you
Answer:
536.56 m/s
Explanation:
We'll begin by calculating the momentum of the Porsche. This can be obtained as follow:
Mass (m) of Porsche = 1361 kg
Velocity (v) of Porsche = 26.82 m/s
Momentum of Porsche =?
Momentum = mass × velocity
Momentum = 1361 × 26.82
Momentum of Porsche = 36502.02 Kgm/s
Finally, we shall determine the velocity you need to be running with in order to have the same momentum as the Porsche. This can be obtained as follow:
Your Mass = 68.03 kg
Your Momentum = Momentum of Porsche = 36502.02 Kgm/s
Your velocity =?
Momentum = mass × velocity
36502.02 = 68.03 × velocity
Divide both side by 68.03
Velocity = 36502.02 / 68.03
Velocity = 536.56 m/s
Thus you must be running with a speed of 536.56 m/s in order to have the same momentum as Porsche.
A/An _____ is described as a device used to store electrical energy, usually two conductors separated by an insulator.
Answer: A capacitor.
Explanation:
The capacitor is a passive element that is used in electronics to store electrical energy maintaining an electrical field. The simpler case of a capacitor is the parallel plates capacitor.
It consists of two parallel metal plates separated by a distance D, in this case, the air between the plates works as a dielectric, as the plates do not touch each other and are separated by a dielectric, the charge is stored in the surface plates.
There are a lot of other types of capacitors, the most used in actuality may be the cylindrical one, where instead of parallel plates, it uses two concentric cylinders, and the space between the cylinders is filled with a dielectric/insulator.
********************PLEASE HELP******************************************
In your own words, explain why different locations on Earth experience different seasons on any given date.
Be sure your explanation includes the following concepts:
revolution of Earth around the Sun
tilt of the Earth
angle insolation
focus/spread of Sun’s rays
temperature
You must also explain how you know that seasons are not caused by the Earth’s slight changes in distance from the Sun throughout the year.
Do you know how to do this clever ones hmmm?? Describe and explain the motion of a small ball floating on a pond when waves travel across the pond.
Answer:
Ball moves up and down repeatedly on surface because waves consist of successive crests and troughs moving across surface, each crest pushes ball up and each trough allows it to move down.
Explanation:
When a falling meteor is at a distance above the Earth's surface of 2.98 times the Earth's radius, what is its free-fall acceleration caused by the gravitational force exerted on it
Answer:
0.63 m/s²
Explanation:
Given that
Distance of meteor from earth's surface, r = 2.98R,
where R = radius of the Earth.
The force of the meteor due to the Earth is usually given by
F = GMM(a)/(R + r)² where
F = force exerted
G = gravitational constant
M = Mass of the earth
M(a) = mass of meteor
Remember that F = Ma, so applying that here, we have
acceleration of meteor = GM/(R + r)²
where r = 2.98R so that
acceleration of meteor = GM/(R + 2.98R)²
acceleration of meteor = GM/(3.98R)²
acceleration of meteor = GM / 15.84R²
It should be noted that GM/R² = 10, so
acceleration of meteor = 10/15.84
acceleration of meteor = 0.63 m/s²
Therefore as calculated, the acceleration of the meteor is 0.63 m/s²
Two asteroids begin to gravitationally attract one another. If one asteroid has twice the mass of the other, which one experiences the greater force
Answer:
F = G \frac{2 m^{2} }{r^{2} }
action and reaction forces with the same magnitude, but in the opposite direction, one applied to each body.
Explanation:
The force between the asteroids is given by the law of universal gravitation
F = G m₁ m₂ / r²
in this case they give us the mass of each asteroid
m₁ = m
m₂ = 2m
we substitute
F = G m 2m / r²
F = G 2 m² / r²
[tex]F = G \frac{2 m^{2} }{r^{2} }[/tex]
Let's analyze this expression, this is the force that one asteroid exerts on the other, therefore there are two forces, one applied to each asteroid, as the order of the products does not affect the result, the magnitude of the force is the same on each asteroid.
These are action and reaction forces with the same magnitude, but in the opposite direction, one applied to each body.
Consequently the two asteroid experiences the same magnitude of force
Find the height from which you would have to drop a ball so that it would have a speed of 7.4 m/s just before it hits the ground.
Answer:
s = 2.79 m
Explanation:
Given that,
A ball have a speed of 7.4 m/s just before it hits the ground.
Initial velocity of the ball was 0 (at rest)
We need to find the height from where the ball was dropped. It means we need to find the distance covered by it. Let it is h.
Using the third equation of motion to find it as follows :
[tex]v^2-u^2=2as\\\\s=\dfrac{v^2}{2g}\\\\s=\dfrac{(7.4)^2}{2\times 9.8}\\\\s=2.79\ m[/tex]
So, the ball is dropped from a height of 2.79 m.
The height from which you would have to drop a ball so that it would have a speed of 7.4 m/s just before it hits the ground is 2.79m
Equation of motionsAccording to the third equation of motion;
[tex]v^2=u^2+2as[/tex]
where;
v is the final velocity = 7.4m/s
Initial velocity = 0m/s
s is the distance
a = g= 9.8m/s²
Substitute the values into the formula to have:
[tex]7.4^2=0^2+2(9.8)s\\54.76 + 19.6s\\s=\frac{54.76}{19.6}\\ s=2.79m[/tex]
Hence the height from which you would have to drop a ball so that it would have a speed of 7.4 m/s just before it hits the ground is 2.79m
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A car stopped at a red light, begins to accelerate with a constant acceleration of 7.4 m/s^2 during a
time of 2.4 seconds. If the speed limit of the road is 35 mph (about 15.64 m/s), is the car
considered to be speeding at any point?
Answer:
The car is considered to be speeding
Explanation:
The following data were obtained from the question:
Constant acceleration (a) = 7.4 m/s²
Time (t) = 2.4 s
Speed limit = 15.64 m/s
To know if the car speeding at any point, we shall determine the velocity of the car.
This can be obtained as follow:
Constant acceleration (a) = 7.4 m/s²
Time (t) = 2.4 s
Constant velocity (v) =?
a = v/t
7.4 = v / 2.4
Cross multiply
v = 7.4 × 2.4
v = 17.76 m/s
Thus, the velocity of the car is 17.76 m/s.
Comparing the velocity of the car (i.e 17.76 m/s) with the speed limit (i.e 15.64 m/s), we can see that the velocity of the car is higher than the speed limit. Therefore, the car is considered to be speeding.
WILL GIVE BRAINLIEST IF CORRECT!
Estimate the weight of a 1000-kg car that is accelerating at 3m/s/s.
(Use g=10m/s/s)
Answer:
10000N
Explanation:
Given parameters:
Mass of the car = 1000kg
Acceleration = 3m/s²
g = 10m/s²
Unknown:
Weight of the car = ?
Solution:
To solve this problem we must understand that weight is the vertical gravitational force that acts on a body.
Weight = mass x acceleration due to gravity
So;
Weight = 1000 x 10 = 10000N
A 1,000 kg truck initially had a velocity of 9 m/s. A force acts on it for a duration of time. After that force, the truck now has a velocity of 17 m/s. What is the impulse that the truck experienced?
Answer:
8000Ns
Explanation:
Given parameters:
Mass of the truck = 1000kg
Initial velocity = 9m/s
Final velocity = 17m/s
Unknown:
Impulse = ?
Solution:
The impulse experienced by the truck is the the change in momentum of the body.
Impulse = Ft
Momentum = m(v - u)
Ft = m( v - u )
F is the force
t is the time
m is the mass
v is the final velocity
u is the initial velocity
Impulse = 1000(17 - 9) = 8000Ns
Construct an argument from evidence to support the claim that the amount of force needed to accelerate an object is proportional to its mass (inertia).
Answer:
Look Below
Explanation:
Let's say you are kicking certain things. The first object is a soccer ball. Assume the ball is at rest using the Earth frame of reference. If you kick as hard as you can the ball it will go flying. Now change the soccer ball into a bowling ball. If you kick it as hard as you can again. It will not go as far. The same force that you applied to both the soccer ball and bowling ball allow it to accelerate, but the bowling ball which has more mass does not accelerate as much compared to the soccer ball due to the amount of mass it has.
When the Moon is at a distance of 0.25 D from the Earth, the gravitational force on the Moon from the Earth is 16.00 F. At what distance will the force on the Moon be 4.00 F?
Answer:
On the way to the Moon the Apollo astronauts reached a point where the. Moon's gravitational pull became stronger, than the Earth's. (a) Determine the distance of ...
Explanation:
Which list is in order from biggest to smallest? A. Earth Solar system Nebula Galaxy O O B. Universe - Galaxy Solar system Earth O C. Universe Earth Solar system Nebula O D. Solar system som Galaxy – Nebula Earth
Answer:B, universe, galaxy, solar system, earth
Explanation:
A p e x
Answer:
universe, Galaxy, solar system, earth
Explanation:
A P E X
what causes sound to have low pitch
A.Sound Wave with high frequency.
B.sound wave with low frequency.
C.sound wave with large amplitude
D.sound wave with small amplitude
3. A coil of 100 turns encloses an area of 100 cm2. It is placed at an angle of 700 with a
magnetic field of 0.1 Wbm-2. What is the magnetic flux through the coil? If the magnetic
field is reduced to zero in 10-3s, what emf is induced in the coil?
Explanation:
Given that,
Number of turns in the coil, N = 100
Area of the coil, A = 100 cm² = 0.01 m²
It is placed at an angle of 70°.
Magnetic field, B = 0.1 Wb/m²
We need to find the magnetic flux through the coil and the emf is induced in the coil after 10⁻³ s.
Magnetic flux is given by :
[tex]\phi =BA\cos\theta\\\\\text{For N turns},\\\phi =NBA\cos\theta \\\\\phi=100\times 0.1\times 0.01\times \cos(70)\\\\=0.034\ Wb[/tex]
So, the magnetic flux through the coil is 0.1 Wb.
Emf induced in the coil is :
[tex]\epsilon=\dfrac{-d\phi}{dt}\\\\=\dfrac{0.034}{10^{-3}}\\\\=34\ V[/tex]
So, 34V of emf is induced in the coil.
A crate is pulled 7 m across a smooth surface. The tension in the rope pulling the crate is 40 N. If the work on the crate is 247 J, what is the angle the rope makes with the horizontal
Answer:
61.9°
Explanation:
The formula for calculating the workdone is expressed as
Workdone = Fdsin theta
F is the force applied on the crate
d is the distance covered
theta is the angle that the rope makes with the horizontal
Given
F = 40N
d = 7m
Workdone = 247J
Substituting into the formula:
247 = 40(7)sin theta
247 = 280sin theta
sin theta = 247/280
sin theta = 0.88214
theta = arcsin(0.88214)
theta = 61.9°
Hence the angle that the rope makes with the horizontal is 61.9°
A boy walked 4m east then 3m south find the displacement
Answer:
5m
Explanation:
[tex]4^{2}+3^{2}=5^{2}\\5^{2}=25[/tex]
Use the Pythagorean theorem to calculate the long edge of the triangle, which would be his displacement.
How fast is a 30 kg child runnning if her kinetic energy is 500 J?
[tex]\displaystyle v = 5.7735 \ m/s[/tex]
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightEquality Properties
Physics
SI Units
Speed is m/s (meters per second)Energy is J (Joules), equal to 1 N/m (newton per meter)Mass is kg (kilograms)Energy
Kinetic Energy Formula: [tex]\displaystyle KE = \frac{1}{2} mv^2[/tex]
KE is Kinetic Energy (in J)m is mass (in kg)v is velocity (in m/s)Explanation:Step 1: Define
Mass m = 30 kg
Kinetic Energy KE = 500 J
Step 2: Solve for v
Substitute [KEF]: [tex]\displaystyle 500 = \frac{1}{2}(30)v^2[/tex]Multiply: [tex]\displaystyle 500 = 15v^2[/tex]Isolate v term: [tex]\displaystyle \frac{100}{3} = v^2[/tex] Isolate v: [tex]\displaystyle \frac{10\sqrt{3} }{3} = v[/tex]Rewrite: [tex]\displaystyle v = \frac{10\sqrt{3} }{3} \ m/s[/tex]Evaluate: [tex]\displaystyle v = 5.7735 \ m/s[/tex]A horizontal force of 5.0-N accelerates a 4.0-kg mass, from rest, at a rate of 0.50 m/s^2 in the positive direction. What friction force acts on the mass
Answer:
3N
Explanation:
The frictional force always acts directly opposite to the force of motion, that is it opposes motion. According to the Newton second law of motion:
Sum of horizontal forces = 0
Hence:
5N - 4(0.5) - F = 0
5 - 2 = F
F = 3N
what is kinetic energy
Answer:
Kinetic energy is energy of motion
Explanation:
Of potential energy which is energy that is stored
Show how multiplying both sides of the acceleration equation a equals F net over in Byam results in the net force equation F net equals MA
In order to find the formula for net force, multiply both sides by mass.
What is Newton's Second law of motion?Newton's second law of motion states that the rate of change of momentum is directly proportional to the force applied.
Given is the acceleration as the ratio of net force and mass.
We can write acceleration as -
a = F[net]/m
If we have to find the formula for net force, we will multiply both sides by mass (m). Therefore -
a x m = (F[net]/m) x m
am = F[net]
or
F[net] = ma
Therefore, in order to find the formula for net force, multiply both sides by mass.
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Super fine 40-gauge copper wire has a diameter of only and weighs only . Suppose a spool of 40-gauge wire weighs less after some wire is pulled off to wind a magnet. How could you calculate how much wire was used
This question is incomplete, the complete question is;
Super fine 40-gauge copper wire has a diameter of only 0.080 mm and weighs only 44.5 g/km. Suppose a spool of 40-gauge wire weighs 205 g less after some wire is pulled off to wind a magnet. How could you calculate how much wire was used ?
Answer: length of wire to be used is 4.6067 km
Explanation:
Circular diameter = d mm
Linear mass density of wire = μ g/km
let m be the mass of wire un-winded from spool to wind a magnet.
If M is mass of wire initially
then
Δm = M - m { which represents decrease of mass }
Also if L rep the length of wire pulled off,
then
Δm = μ × L grams
⇒ L = Δm/μ km
now given that weight Δm = 205 g and length per unit weight μ = 44.5 g/km
we substitute
L = 205 g / 44.5 g/km
L = 4.6067 km
Therefore length of wire to be used is 4.6067 km
Two inductors are connected in parallel to a 120 volt, 60 Hz line. The values are 5 H and 2 H. The total inductive reactance is
Answer:Total Inductive reactance XL =538.63 Ω
Explanation:
Parallel combination for Effective inductance is calculated as
L total = [tex]\frac{1}{1/L1 + 1/L2 + ... 1/Ln}[/tex]
=[tex]\frac{1}{1/5 + 1/2}[/tex]
[tex]\frac{1}{0.2 + 0.5 \\}[/tex]
=[tex]\frac{1}{0.7}[/tex]
=1.42857H
Inductive reactance XL = 2 πFL
where f= frequency= 60Hz
L= Effective inductance=1.42857H
Inductive reactance , XL = 2 X 3.142 X 60 X 1.42857
=538.63Ω