What is the measure of angle G? Type only the number:

9514 1404 393

Answer:

  25%

Step-by-step explanation:

The markup is the difference between the selling price and the cost price.

  markup = (500)($10) - $4000 = $1000

Then the percent markup of the cost price is ...

  markup/(cost price) = $1000/$4000 × 100% = 25%

The percentage markup was 25%.

[tex] \LARGE{ \underline{ \tt{Required \: answer:}}}[/tex]

We have:

We need to find:

Solution:

Let the width be w. Then the length would be:

➝ Length = 2(width) - 3

➝ l = 2w - 3

Area of rectangle: l × b

➝ Length × width = 35 cm²

➝ (2w - 3)w = 35

➝ 2w² - 3w - 35 = 0

Now finding value of x by middle term factorisation,

➝ 2w² - 10w + 7w - 35 = 0

➝ 2w(w - 5) + 7(w - 5) = 0

➝ (2w + 7)(w - 5) = 0

Hence,

Therefore,

⛱️ [tex] \large{ \blue{ \bf{FadedElla}}}[/tex]

let x represent the rectangle's width;

thus;

Width = x

Length = 2x - 3

Area = 35 sq. cm.

Area = Length × Width

35 = (2x - 3)(x)

35 = 2x^2 - 3x

2x^2 - 3x - 35 = 0

Factorizing:

x = 5 or -3.5

but width is a scalar quantity and cannot be negative:

Hence:

Width = 5 cm.

Length = 2(5) - 3 = 7 cm.

6x = 41

x = 7 to the nearest whole number.

Width = 7 cm.

Length = 2(7) - 3 = 11 cm.

Answer:

1,3,4

Step-by-step explanation:

Answer:

[tex]f(3) = \frac{-26}{9}[/tex]

[tex]f(2 + h) = \frac{- 11 - 12h - 12^2}{4 + 4h + h^2}[/tex]

Step-by-step explanation:

Given

[tex]f(x) = \frac{1}{x^2} - 3[/tex]

Required

Find f(3) and f(2 + h)

Solving f(3)

Substitute 3 for x in [tex]f(x) = \frac{1}{x^2} - 3[/tex]

[tex]f(3) = \frac{1}{3^2} - 3[/tex]

[tex]f(3) = \frac{1}{9} - 3[/tex]

Take LCM

[tex]f(3) = \frac{1 - 27}{9}[/tex]

[tex]f(3) = \frac{-26}{9}[/tex]

Solving f(2 + h)

Substitute 2 + h for x in [tex]f(x) = \frac{1}{x^2} - 3[/tex]

[tex]f(2 + h) = \frac{1}{(2 + h)^2} - 3[/tex]

[tex]f(2 + h) = \frac{1}{(2 + h)(2 + h)} - 3[/tex]

[tex]f(2 + h) = \frac{1}{4 + 2h + 2h + h^2} - 3[/tex]

[tex]f(2 + h) = \frac{1}{4 + 4h + h^2} - 3[/tex]

Take LCM

[tex]f(2 + h) = \frac{1- 3(4 + 4h + h^2)}{4 + 4h + h^2}[/tex]

[tex]f(2 + h) = \frac{1- 12 - 12h - 12^2}{4 + 4h + h^2}[/tex]

[tex]f(2 + h) = \frac{- 11 - 12h - 12^2}{4 + 4h + h^2}[/tex]

Answer:

x<4.7

Step-by-step explanation:

2(x-2)+8.6<14

2x-4+8.6<14

2x=4.6<14

2x<14-4.6

2x<9.4

_____

x<4.7

                                mom said its my turn to be brainliest answer ;0

                                also, help me on my math hw maybe ?

Answer: x < 4.7

Step-by-step explanation:

Answer:

1.   y=2x -12

2. 2x-y=12

3.y=2/3x 11/3

Step-by-step explanation:

Answer:

Step-by-step explanation:

Yes

Answer:

Step-by-step explanation:

No, I don't agree with Daryl. If you multiply -3 by 2, you will get -6. -6 is not equal to -32, which means that they don't have the same value, so Daryl is wrong.

Answer:

Step-by-step explanation:

4000*1/10= $400

Answer:

Box 1= 1

Box 2 =-8

Box 3= -2

Step-by-step explanation:

Plug in the numbers that are provided where you see x

-3(x) +8    x=3

Answer:

No,

Step-by-step explanation:

Guess why

If you do x = - 2

Then y become 1,

Which is not matched to

-5

Answer:

y=-9x+9

Step-by-step explanation:

There are only two like terms in the equation which I have underlined.

y= 3x - 12x +9

To simplify it, you combine the like terms and get your equation in standard form.

Answer:

(-2, 33) and (5, - 16)?

A. 7x- y=51

B. 7x+ y= -47

C. 7x+ y= -14 D. 7x+y= 19

Step-by-step explanation:

Answer:

37

Step-by-step explanation:

I hope I helped have a great day.

Answer:

a) The function is: f(x, y) = x + y.

The constraint is: x*y = 196.

Remember that we must write the constraint as:

g(x, y) = x*y - 196 = 0

Then we have:

L(x, y, λ) = f(x, y) +  λ*g(x, y)

L(x, y,  λ) = x + y +  λ*(x*y - 196)

Now, let's compute the partial derivations, those must be zero.

dL/dx =  λ*y + 1

dL/dy =  λ*x + 1

dL/dλ = (x*y - 196)

Those must be equal to zero, then we have a system of equations:

λ*y + 1 = 0

λ*x + 1 = 0

(x*y - 196) = 0

Let's solve this, in the first equation we can isolate  λ to get:

λ = -1/y

Now we can replace this in the second equation and get;

-x/y + 1 = 0

Now let's isolate x.

x = y

Now we can replace this in the last equation, and we will get:

(x*x - 196) = 0

x^2 = 196

x = √196 = 14

then the minimum will be:

x + y = x + x = 14 + 14 = 28.

b) Now we have:

f(x) = x*y

g(x) = x + y - 196

Let's do the same as before:

L(x, y, λ) = f(x, y) +  λ*g(x, y)

L(x, y, λ) = x*y +  λ*(x + y - 196)

Now let's do the derivations:

dL/dx = y + λ

dL/dy = x + λ

dL/dλ = x + y - 196

Now we have the system of equations:

y + λ = 0

x + λ = 0

x + y - 196 = 0

To solve it, we can isolate lambda in the first equation to get:

λ = -y

Now we can replace this in the second equation:

x - y = 0

Now we can isolate x:

x = y

now we can replace that in the last equation

y + y - 196 = 0

2*y - 196 = 0

2*y = 196

y = 196/2 = 98

The maximum will be:

x*y = y*y = 98*98 = 9,604

Answer:

The area of the shaded region is 3.

Step-by-step explanation:

Since point E lies halfway between AB and BC, the area of the shaded region (As) consists of two identical triangles with base equal to AB and height equal to half the measure of BC:

[tex]A_s=2 * A_t[/tex]

Where At is the area of each triangle.

[tex]\displaystyle A_t=\frac{AB*BC/2}{2}[/tex]

[tex]\displaystyle A_t=\frac{AB*BC}{4}[/tex]

We know AB=3 and BC=2, thus:

[tex]\displaystyle A_t=\frac{3*2}{4}=\frac{6}{4}[/tex]

Simplifying:

[tex]\displaystyle A_t=\frac{3}{2}[/tex]

Finally:

[tex]\displaystyle A_s=2 * \frac{3}{2}[/tex]

[tex]A_s=3[/tex]

The area of the shaded region is 3.

Note the area of the shaded region is half the area of the rectangle.

Answer:

[tex]\lim _{x\to \:0}\left(\frac{\sqrt{1+x}+\left(1+x\right)^7-2}{7}\right)\\\\\frac{\sqrt{1+0}+\left(1+0\right)^7-2}{7}\\\\then\ simplify\\=0[/tex]

Step-by-step explanation:

Answer:

22/7 * 8.5 * 8.5 = answer

Answer:

Step-by-step explanation:

A = π r² ≈ 3.14 × (8.5)² = 226.865 m²

Answer:

i think the aswer s 60,000

Step-by-step explanation:

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

[tex]5x - 60 > 8x[/tex]

[tex]8x < 5x - 60[/tex]

Subtract sides 5x

[tex] - 5x + 8x < - 5x + 5x - 60[/tex]

[tex]3x < - 60[/tex]

Subtract sides 3

[tex] \frac{3x}{3} < \frac{ - 60}{3} \\ [/tex]

[tex]x < - 20[/tex]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Answer: The answer is x<–20.

Step-by-step explanation: Let’s solve the inequality step by step.

• Step 1 Subtract 8x from both sides. Do the rest of the step by step of the following inequality.

Answer:

6 teams

Step-by-step explanation:

They can only make 5 teams with 8 kids on each. 1 child will remain

Answer:

Using distributive property to remove the parentheses [tex](x+12)8[/tex] we get [tex]8x+96[/tex]

Step-by-step explanation:

We need to use distributive property to remove the parentheses (x+12)8

According to distributive property of multiplication over addition:

[tex]a(b+c)=ab+ac[/tex]

Now, using the above distributive property to solve the given question. Multiply 8 with terms inside the bracket and solving:

[tex](x+12)8\\=8x+8*12\\=8x+96[/tex]

So, using distributive property to remove the parentheses [tex](x+12)8[/tex] we get [tex]8x+96[/tex]

Answer:

C.) (2,-2) and (0,-2)

Step-by-step explanation:

The coordinates would have to have y values of -2, because the line plotted only has y values of -2

Answer:

C.

Step-by-step explanation:

Answer:

I think the answer is (c) 3

Answer: I hope I’m not too late, but the answer is A.) 12

Step-by-step explanation:

Answer:

g(x) = √(2x)

Step-by-step explanation:

f(x) = 3x^2

g(f(x)) =√6x

g(3x^2) = x√6

g(x) must be √(2x)

because if we  substitute  x = 3x^2 in this we get

(√2(3x^2))

= √2√3√(x^2)

= √6 x