What kind of bond is formed between a metal and a metal
O All of the above
O lonic bond
O Metallic bond
O Covalent bond

Answer:

100watts

Explanation:

Given parameters:

Workdone  = 500Nm

Time taken = 5s

Unknown:

Power in watts = ?

Solution:

Power is the rate at which work is done;

   Power  =[tex]\frac{workdone }{time}[/tex]

Input the parameters and solve;

   Power = [tex]\frac{500}{5}[/tex]  = 100watts

Answer:

The net force = 0

Explanation:

The given information includes;

The mass of the crate = 250 kg

The way the helicopter lifts the crate = Uniformly (constant rate (speed), no acceleration)

In order to pull the crate upwards, the helicopter has to provide a force equivalent to the weight of the crate keeping the helicopter on the ground.

The weight of the crate = The mass of the crate × The acceleration due gravity acting on the crate

The weight of the crate, [tex]F_w[/tex]↓ = 250 kg × 9.81 m/s² = 2,452.5 N

The force the helicopter should provide to just lift the crate, [tex]F_{(helicopter)}[/tex]↑ = The weight of the crate = 2,452.5 N

The net force, [tex]F_{(net)}[/tex] = [tex]F_{(helicopter)}[/tex]↑ - [tex]F_w[/tex]↓ = 2,452.5 N - 2,452.5 N = 0

The net force = 0.

Answer:

2 minutes or 120 seconds

Explanation:

The answer is 2 minutes or 120 seconds because 36 km is 36000 m and 36000 divided by 300 is 120, so the answer is 120 seconds, and converted to 2 minutes. Hope it helps!

Answer:

Explanation:

Hope this helps, cheers

Answer:

66.6 or it could be 66.66 one of those

Explanation:

Answer:

The horizontal component of the velocity is approximately 13.22 m/s

Explanation:

The velocity of the kick which the football player gives the ball = 21 m/s

The angle of the path taken by the ball = 51°

The velocity can be represented vectorially, showing the vertical and horizontal components as follows;

v = 21 × cos(51°)·[tex]\hat i[/tex] + 21 × sin(51°)·[tex]\hat j[/tex]

Where we have;

The horizontal component of the velocity = 21 × cos(51°)

The vertical component of the velocity = 21 × sin(51°)

Therefore;

The horizontal component of the velocity = 21 × cos(51°) ≈ 13.22 m/s

The horizontal component of the velocity ≈ 13.22 m/s.

Answer:

35.47 m/s

Explanation:

[tex]r = \sqrt{( - 23)^{2} + (27) ^{2} }[/tex]

=35.57

Answer:

1) t_total = 140 min ,  v = 126.7 m / min ,  2)  v = 0.628 m / s ,

3) v = 0.592 m / s ,  θ = -39.3 º

Explanation:

Here we have some short kinematics problems

1) d₁ = 4200 m at T1 = 25 min

    d₂ = 4.54 km at t2 = 1 h

    d₃ = 9000 m at t3 = 55 min

of the statement the direction of each route is the same

Let's reduce the distances to the SI system

     d₂ = 4.54 km (1000 m / 1 km) = 4540 m

     t₂ = 1 h (60 min / 1 h) = 60 min

Total time is

    t_total = t1 + t2 + t3

   t_total = 25 + 60 +55

   t_total = 140 min

the distance is

    d_total = 4200 + 4540 +9000

     d_total = 17740 m

with movement it is in one dimension and all displacement is in the same direction, distance equals displacement.

Speed ​​is

       v = 17740/140

       v = 126.7 m / min

in the direction of travel

Speed ​​is the modulus of speed

        | v | = 126.7 m / min

2) the angular velocity is

        w = θ / t

In this exercise

        t = 2 min (60 s / 1min) = 120 s

        θ = 30 rev (2π rad / 1 rev) = 60π rad

         w = 60π / 120

         w = 1.57 rad / s

linear velocity  is

        v = w r

        v = 1.57 0.40

        v = 0.628 m / s

velocity is the speed tangential to the  trajectory

3) the data for this exercise are

     distance = (number of steps) (distance of one step)

         d₁ = 500 0.40 m = 200 m West

         d₂ = 400 0.35 m = 140 m North

         d₃ = 300 0.30 m = 90 m East

in a total time of t = 2 min and 120 s

           t = 2  60 + 120 = 240 s

the distance traveled is

x axis we assume the direction towards + x (East) positive

           x_total = d₃ -d₁

           x_total = 90-200 = -110 m

y axis  

          y_total = d₂

          y_total = 140 m

we use the Pythagorean theorem to find the distance0

           D = √ (x_total² + y_total²)

           D = √ (110² + 90²)

           D = 142.13 m

The speed is

           v = D / t

            v = 142.13 / 240

           v = 0.592 m / s

speed is

           v = 0592 m / s

           tan θ = Y / X

           θ = tan -1 y / x

           θ = tan -1 (90 / (- 110))

           θ = -39.3 º

4) This angle is measured on the positive side of the x axis in a clockwise direction

          θ = 1.5 rev (2π rad / 1 rev) = 3π rad

           t = 90 s

the angular velocity is

           w = θ / t

           w = 3πi / 90

           w = 0.1047 rad / s

the speed is

            v = w R

            v = 0.14047 250

            v = 26.17 m / s

velocity is tangent to path

Answer:

synthesis and combustion

double replacement

single replacement

decomposition only

in that exact order edge 2020

The presented reactions are:

S + O₂ ⇒ SO₂    Synthesis or combination

CaCl₂ + AgNO₃ = Ca(NO₃)₂ + 2 AgCl   Double displacement

Zn + CuSO₄ = Cu + ZnSO₄   Single displacement

2 Na₂O = 4 Na + O₂   Decomposition

Let's consider and classify the following reactions.

S + O₂ ⇒ SO₂

This is a synthesis or combination reaction. 2 compounds combine to form another.

CaCl₂ + AgNO₃ = Ca(NO₃)₂ + 2 AgCl

This is a double displacement reaction. Both compounds exchange their cations and anions.

Zn + CuSO₄ = Cu + ZnSO₄

This is a single displacement reaction. A metal displaces other metal from its salt.

2 Na₂O = 4 Na + O₂

This is a decomposition reaction. A compound decomposes into 2 other compounds.

The presented reactions are:

S + O₂ ⇒ SO₂    Synthesis or combination

CaCl₂ + AgNO₃ = Ca(NO₃)₂ + 2 AgCl   Double displacement

Zn + CuSO₄ = Cu + ZnSO₄   Single displacement

2 Na₂O = 4 Na + O₂   Decomposition

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Answer:

Explanation:

plasma, gas, liquid, solid

Answer:

The weight is 348.4 N

Explanation:

Effect of the Altitude on the Acceleration of Gravity

The effect of gravity decreases with altitude because greater altitudes mean greater distances from the Earth's center.

The practical formula to calculate the gravity as a function of the altitude h is:

[tex]{\displaystyle g_{h}=g_{0}\left({\frac {R_{\mathrm {e} }}{R_{\mathrm {e} }+h}}\right)^{2}}[/tex]

Where go is the conventional gravitational acceleration = [tex]9.80665\ m/s^2[/tex]

R is the Earth's mean radius at the equator = 6,378 Km

h is the altitude.

At a height of h=800 Km, the acceleration of gravity is:

[tex]{\displaystyle g_{h}=9.80665 m/s^2\left(\frac {6,378 Km }{6,378 Km+800Km}}\right)^{2}}[/tex]

Calculating:

[tex]g_h=7.74\ m/s^2[/tex]

The weight is the product of the acceleration of gravity by the mass of the object, thus:

[tex]W=45\ Kg\cdot 7.74\ m/s^2=348.4\ N[/tex]

The weight is 348.4 N

Answer:

it is kastle Meyer fasure

Answer:

you would do multiplication, d=rt. (distance=d rate=r time=t).

Explanation:

You already have all the variables figure out so just plug in the numbers.

For an easier equation you would just do .6*45=27, the 27 is the total kilometers in 45 minutes.

a) Answer:

Momentum = 6 kgm/s

Explanation:

Momentum = mass × velocity

Given that,

Therefore, momentum = (0.02 × 300)kgm/s

Momentum = 6 kgm/s

b) Answer:

Momentum =80 kgm/s

Explanation:

Momentum = mass × velocity

Given that,

Therefore, momentum = (40 × 2)kgm/s

Momentum = 80 kgm/s

c) Answer:

Momentum = 800 kgm/s

Explanation:

Momentum = mass × velocity

Given that,

Therefore, momentum = (200 × 4)kgm/s

Momentum =800 kgm/s

A chemical structure of a molecule includes the arrangement of atoms and the chemical bonds that hold the atoms together. The 2-HEPTANONE molecule contains a total of 21 bond(s) There are 7 non-H bond(s), 1 multiple bond(s), 4 rotatable bond(s), 1 double bond(s) and 1 ketone(s) (aliphatic).

:/ hope this helps

Answer:

ok

Explanation:

Answer: A chemical formula is a way of showing and representing information about a chemical proportion of atoms that constitute a particular chemical compound or molecule

Answer:

Let's define:

The position zero will be in the first point where the truck and police car meet. (So the initial position of both vehicles is zero)

Then, the position equation for the truck is:

T(t) = 20m/s*t

Where t is our variable, time in seconds.

Now, at t = 5s, the car starts accelerating.

Ac(t) = 2m/s^2                    for( t ≥ 5s)

For the velocity of the car, we must integrate that.

V(t) = (2m/s^2)*(t - 5)           for (t ≥ 5s)

Where i introduced a little change in the variable because the velocity of the car starts to increase for t larger than 5 seconds.

For the position of the car we integrate again.

C(t) = (1m/s)*(t - 5)^2            for (t ≥ 5s)

Now, let's answer the questions:

Determine the time at which the speed of the truck is equal to the speed of the police car.

Then we must have:

V(t) = (2m/s^2)*(t - 5)  = 20m/s.   (Remember that we only can use times requal or larger than 5 seconds).        

2m/s^2*t - 10m/s = 20m/s

2m/s^2*t = 30m/s

t = (30/2) s = 15s

The velocities of both vehicles will be the same after 15 seconds.

t1 = 15s

How the positions will compare at this time?

The easier thing will be to evaluate the position equation of each vehicle in this time:

T(15s) = 20m/s*15s = 300m

C(15s) = (1m/s^2)*(15s - 5s)^2 = (1m/s^2)*(10s)^2 = 100m.

Then we can see that the truck is 200m ahead of the car.

But remember that the police car is accelerating, so the velocity will keep increasing meaning that eventually, the car will catch the truck.

Answer:

c

Explanation:

An object's speed is the characteristic which is related to kinetic energy but not the potential energy. Thus, the correct option is C.

The kinetic energy of an object is the energy which it possesses due to the motion of the object. Kinetic energy is defined as the work which is needed to accelerate an object of a given mass from rest position to its stated velocity. Having gained this amount of energy during the acceleration of the object, the object maintains this kinetic energy unless its speed changes or it experiences acceleration.

Kinetic energy is directly proportional to the mass of the object and to the square of the velocity of the object, the expression is:

K.E. = 1/2 m × v²

where, KE = Kinetic energy,

m = mass of the object,

v = velocity of the object.

Therefore, the correct option is C.

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Answer:

System management

Explanation:

Answer:

The answer is C.) Lacks all 3 types of antigens.

Answer:

i. 7.5 m

ii. 15000 N

Explanation:

Area under vt graph shows the displacement

so area of triangle ABE= 1/2×15×2

=7.5 m

ii) F=ma

here, m=1000kg

and a=v-u/t

=15-0/1

a=15

F=1000×15=15000N

Answer:

B, 4π^2r/T^2

Explanation:

Im on the same quiz, and I'm pretty sure this is the right answer cause I found it on 4 other websites. Good luck

Answer:

The answer is D.

Explanation:

Answer:

the umbra and penumbra

Explanation:

The two parts of a shadow are the umbra and penumbra.

A shadow is an expression formed when light from a source is cut blocked by an opaque body.

Most shadows are made up of two parts, umbra and penumbra.

The umbra is directly formed by light which impinges on an opaque body and it completely cut off.

Answer: 3.75 m/s

Explanation:

Here's what you know: The car has mass 1500 kg, and initial velocity 15.0 m/s.  The truck has mass 4500 kg and initial velocity 0 m/s.  The final mass is 6000 kg (4500 kg plus 1500 kg, because they stick together) and we are looking for the final velocity.  Using the formula p = mv, and the concept that p before equals p after, the p of the car plus p of the truck equals the p of them together. So, 1500 x 15 + 4500 x 0 = 6000 x v final.  22500 = 6000 v, and v = 3.75 m/s.  The velocity is positive, and the initial velocity of the car was positive, so the two vehicles together are traveling to the south just like the car was initially.

Answer:

The pushing of the car by you and your friends is the applied force and when the car moves, it means that the velocity has changed thus causing the movement or acceleration.

Explanation:

Newton's work on forces regarding motion can never be neglected by scientists. Sir Isaac Newton when he was alive, among several of his works he proposed the three laws guiding the forces of motion. In this question we are only going to be treating only one out of the three Newton's Law of motion and that is the second Law Of Newton's laws of motion.

The second Law Of Newton's laws of motion states that the acceleration of an object is directly proportional to the applied force and inversely proportional to the object's mass.

(1). Now, to the question: " How are you and your friends applying Newton's second law of motion here? "

The pushing of the car by you and your friends is the applied force and when the car moves, it means that the velocity has changed thus causing the movement or acceleration.

According to the law, the more the Force, the more the acceleration.

(2). For the second part of the question, " What if the car you were traveling in was a large SUV?"

From the law stated above we see that the acceleration is inversely proportional to the mass, thus if the car is a large SUV, It means that more force is needed to change the car's velocity.

Answer:

When a friend joins you in pushing the small car, the net force on it increases. Therefore, it starts to move. The mass of a SUV is much greater than that of a small car. You would thus need the help of more friends to help push it.

Explanation:

Plato/Edmentum

Answer:

a_AV - 15 m/s – 36 m/s =-70 m/s2. At. 3.0 s.

Explanation:

The average acceleration of the car as it slows down is  -5 m/s².

Given is a race car that slows down from 36 m/s to 15 m/s in 3 seconds.

initial velocity [u] = 36 m/s

final velocity [v] = 15 m/s

time taken [Δt] = 3 s

We can calculate the acceleration as follows -

a = Δv/Δt

a = (v - u) / Δt

a = (15 - 30)/3

a = -15/3

a = -5 m/s²

Therefore, the average acceleration of the car as it slows down is

-5 m/s².

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