Which equation is graphed in the picture.

PLEASE HELP!!!!!

Answer:

3.5972174e+13 could i get brainliest please?

Step-by-step explanation:

Answer:

B) Yes, by SAS

Step-by-step explanation:

AB=FG(given)

AC=EG(given)

ABC=EFG (given

Answer:

Yes. By SAS.

Step-by-step explanation:

both share ll l and than an angle.

so side angle side is only possibility

brainliest appreciated!

Answer:

y=-10x+3

Step-by-step explanation:

The slope is -10

Answer:

3/5

Step-by-step explanation:

Answer:

[tex]\frac{3}{5}[/tex]

Step-by-step explanation:

Operations With Fractions

Evaluate the expression:

[tex]\displaystyle \frac{\frac{3}{4}}{\frac{5}{4}}[/tex]

The division of fractions is can be done by multiplying the fraction on the numerator by the reciprocal of the fraction on the denominator:

[tex]\displaystyle \frac{\frac{3}{4}}{\frac{5}{4}}=\frac{3}{4}\cdot\frac{4}{5}[/tex]

Simplifying:

[tex]\displaystyle \frac{\frac{3}{4}}{\frac{5}{4}}=\frac{3}{5}[/tex]

Answer: [tex]\frac{3}{5}[/tex]

Answer:

a) $66

b) $48 + $3x

Step-by-step explanation:

4(12)=48

3(6)=18

48+18=66

---------------

4(12)=48

Each snack is $3, so is the bought x snacks, it would be $3x

She would pay $48 on movie tickets and $18 on snacks which would be a grand total of $66. If she bought x amount of snacks the equation would be 3x+48

Step-by-step explanation:

Answer:

A. q2 = r2 + s2 – 2rscos(Q)

D. r2 = q2 + s2 – 2qscos(R)

E. s2 = q2 + r2 – 2qrcos(S)

Step-by-step explanation:

The following relation represent the law of cosines.

                  [tex]q^{2}=r^{2}+s^{2} -2rscos(Q) \\\\r^{2}=q^{2}+s^{2} -2qscos(R) \\\\s^{2}=r^{2}+q^{2} -2rqcos(S)[/tex]

The law of cosine states that the square of any one side of a triangle is equal to the difference between the sum of squares of the other two sides and double the product of other sides and cosine angle included between them.

It is given that, Q, R, and S are the angles of a triangle, with opposite sides q, r, and s respectively.

A diagram is attached below,

From cosines law,

      [tex]q^{2}=r^{2}+s^{2} -2rscos(Q) \\\\r^{2}=q^{2}+s^{2} -2qscos(R) \\\\s^{2}=r^{2}+q^{2} -2rqcos(S)[/tex]

Above relation represent law of cosines.

Learn more about the Law of cosines here:

https://brainly.com/question/4372174

Answer:

it depends on what you're doing

what's the name of the topic

Answer:

Step-by-step explanation:

Answer:

denominator i think.

Step-by-step explanation:

Answer: They sold 173 adult tickets and 43 student tickets.

Step-by-step explanation:

Equations:

Solving:

Answer:

B)1:3

plz mark as brainliest

Answer:

Step-by-step explanation:

Daniel = d, Sara = s, Luke = l, Rachel = r

We get below relations:

Sum of ages:

Substitute and solve for s:

Rachel's age is:

Answer:

5 shirts

Step-by-step explanation:

78.25- 3.25 = 75

75/ 15 = 5

Answer:

The equation of a direct proportion is: y=8x

So, the correct option is Option A.

Step-by-step explanation:

We need to find equation of direct proportion.

If y varies directly with x then:

[tex]y\:\alpha \:x\\y=kx[/tex]

Where k is constant of proportionality

So, Now Looking at all the options and comparing it with the general equation of direct proportion [tex]y=kx[/tex]

We get the correct option: y=8x

All other options are not according to direct equation

The equation of a direct proportion is: y=8x

So, the correct option is Option A.

Answer:

1

Step-by-step explanation:

Use the coordinates of the points to determine the slope

slope = Δy/Δx = (8-7)/(5-4) = 1

Answer:

i do believe the answer is 6/7

Answer: 32 sq m.

Step-by-step explanation: add 2,4,and 2 for length of bottom rectangle(8) then multiply that by 3 for area- 24. top would be multiplying 4 by 2- 8. Add 2 areas together and get 32.

Answer:

Sample size is [tex]n=423[/tex]

Step-by-step explanation:

Given that,

Margin of error [tex]=4[/tex]%

Confidence level [tex]=90[/tex]%

Suppose, sample proportion[tex]=0.5[/tex]

        i.e. [tex]\hat{P}=0.5[/tex]

We know that,

     Margin of error [tex]=2^*\sqrt{\frac{\hat{p}(1-\hat{p})}{n} }[/tex]

 ∴ [tex]1.64\sqrt{\frac{0.5(0.5)}{n} } \leq 4\%[/tex]

[tex]\Rightarrow 1.64\sqrt{\frac{0.25}{n} } \leq 0.04[/tex]

[tex]\Rightarrow \frac{0.5}{\sqrt{n} } \leq \frac{0.04}{1.64}[/tex]

[tex]\Rightarrow \frac{0.5}{\sqrt{n} } \leq 0.0243[/tex]

[tex]\Rightarrow \sqrt{n}\geq \frac{0.5}{0.0243}[/tex]

[tex]\Rightarrow \sqrt{n}\geq 20.57[/tex]

squaring on both side,

∴ [tex]n=423.1249[/tex]

Hence, the sample size is,

   [tex]n=423[/tex]

Hence, the correct option is [tex](b).[/tex]

Answer:

423

Step-by-step explanation:

Answer:

24 %

Step-by-step explanation:

thats easy

Answer:

Using the future value (FV) formula,

R = .10/12

N = 12*30

P = 400

Your future value would be $904,195.17

Step-by-step explanation:

Answer:

0.9830 = 98.30% probability that the sum of three one-pound bags exceeds the weight of one three-pound bag

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Three one pound bags:

3 one pound mags, which have mean 1.18 and standard deviation of 0.07. The mean is 1.18 multiplied by 3, and the standard deviation will be 0.07 multiplied by the square root of 3. So

[tex]\mu_{1} = 3*1.18 = 3.54[/tex]

[tex]\sigma_{1} = 0.07\sqrt{3} = 0.1212[/tex]

Three pound bags:

Mean 3.22, standard deviation 0.09. So

[tex]\mu_{2} = 3.22, \sigma_{2} = 0.09[/tex]

What is the probability that the sum of three one-pound bags exceeds the weight of one three-pound bag?

Here, we work with the subtraction of the normal variables. The mean is the subtraction of the means, and the standard deviation is the square root of the sum of the variances. So

[tex]\mu = \mu_{1} - \mu_{2} = 3.54 - 3.22 = 0.32[/tex]

[tex]\sigma = \sqrt{\sigma_{1}^2 + \sigma_{2}^2} = \sqrt{0.1212^2+0.09^2} = 0.151[/tex]

This is the probability of the subtraction being positive, that is, 1 subtracted by the pvalue of Z when X = 0. Then

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{0 - 0.32}{0.151}[/tex]

[tex]Z = -2.12[/tex]

[tex]Z = -2.12[/tex] has a pvalue of 0.0170

1 - 0.0170 = 0.9830

0.9830 = 98.30% probability that the sum of three one-pound bags exceeds the weight of one three-pound bag

Answer:

14ft

Step-by-step explanation:

Since the scale is 2in : 7ft, so you would do 7x2 which gets you to 14.

(You would do 7x2 because 4 in/2 in = 2in, that's where the 2 comes from, and 7 because 7ft is part of the scale.)

Hope this helps :D

Answer:

-5

Step-by-step explanation:

gradient or slope of line: m = (y'-y)/(x'-x)

line pass (-2,5) (-1,0) (0,-5)

use any of two points: m = (0-5) / (-1 - -2) = -5/1 = -5

Answer:

my dad left me

Step-by-step explanation:

my dad left me

Answer:

$430,000

Step-by-step explanation:

1,000,000 * 0.43

Answer:

3)  [tex]f^{-1}(x)=\frac{4x+3}{5}[/tex]

Answer:

64/4

Have an amazing day!

Answer:

Use y=mx+b

Step-by-step explanation:

A linear relationship (or linear association) is a statistical term used to describe a straight-line relationship between two variables. Linear relationships can be expressed either in a graphical format or as a mathematical equation of the form y = mx + b.

To solve the problem, you use the equation y=mx+b

Answer:

[tex]f(x) = - \frac{5}{2} x + 4[/tex]

Answer:

[tex]\left \{ {{x=3} \atop {y=-7}} \right.[/tex]

Step-by-step explanation:

We can directly substitute y of the first equation to the second equation.

-2x - 1 = 3x - 16

5x = 15

x = 3

Substituting back to any of the two equations, we get y = -2(3)-1 = -7.  If you check with the second equation, y = 3(3)-16 = -7 as well.

Therefore [tex]\left \{ {{x=3} \atop {y=-7}} \right.[/tex].