Which of the following is not a natural
way water is stored in the water cycle?
A Stream
B. Pond
C. Iceberg
D. Cup

Explanation:

When Reggie's car turned eastward, his books continued heading northward, causing them to slide off the top of his car and fall.

were is the opshons.

Answer:

Like other legumes, peanut plants improve the soil by adding nitrogen, even as they grow tasty, nutritious nuts for this season's harvest. But peanuts need help as they take nitrogen from the air and "fix" it into the soil via their root systems.

Explanation:

[tex]\purple{\tt{\huge{Answer}}}[/tex]

CH3COOH is an accepted and common form of writing the structure of acetic acid (commonly known as vinegar when diluted in water).

Answer:

sndnmxixixisijwiw

Explanation:

jeejndn jzjaisisp

Answer:

1 and 2

Trigonal planar

Tetrahedral

Trigonal Planar

Linear

Bent ( v- shape)

Explanation:

The highlighted atoms has a delocalized lone pair - 1 and 2

All sp2-hybridized carbon atoms have geometry- Trigonal planar

All sp3-hybridized carbon atoms have geometry - Tetrahedral

The nitrogen atom has geometry - Trigonal Planar

The oxygen atom of the C=O bond has geometry - Linear

and the other oxygen atom has geometry - Bent ( v- shape)

P.S - The correct question is -

Ramelteon has been an aromatic compound with 3 ring structure followed by the aliphatic chain.

The drug has antagonist structure to the melatonin and has been used to treat insomnia by acting as the melatonin representative.

The labelled atom in the structure is oxygen of the pentane ring, nitrogen in the aliphatic chain, and carbonyl oxygen.

The delocalized lone pair has been observed in the compound which has been contributing to the resonating structure. The delocalized lone pair ion the given structure is oxygen of the pentane ring, and nitrogen in the aliphatic chain.

The geometry of the atom has been based on the hybridization and the lone pairs.

The geometry of [tex]\rm sp^2[/tex] hybridized carbon has been trigonal planar. The geometry of [tex]\rm sp^3[/tex] hybridized carbon atom has been tetrahedral. The nitrogen in the chain has trigonal planar geometry. The C=O oxygen has been comprising  linear geometry, while the oxygen has bent v shape.

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Explanation:

Mole ratio of NaOH to H2O = 2 : 1

Moles of H2O = 1.85mol * (1/2) = 0.925mol.

Mass of H2O = 0.925mol * (18g/mol) = 16.65g.

Answer:

16.65 grams of water can be produced with 1.85 moles of NaOH.

Explanation:

Mole ratio of NaOH to H2O = 2 : 1

Number of moles of water = (1/2)×1.85= 0.925 moles

Molar mass of water (H2O) = 18g/mol

Mass of the right water = 18g/mol×0.925 mol=16.65 grams

Answer:

3.4027x10^-22

Explanation:

Answer:

Na sodium or Rb rubidium

Explanation:

Because Na is present in first group all members of group 1 have 1 electron in valence shell and show similar properties.

Answer:

Clouds are water

Explanation:

When a gas gathers up into a cloud,the cloud starts to rain and water comes out of the cloud.

Answer:

Atoms consist of three basic particles: protons, electrons, and neutrons. The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge). The outermost regions of the atom are called electron shells and contain the electrons (negatively charged).

Answer:

[tex]0.1090\ \text{M}[/tex]

Explanation:

Volume of [tex]KOH[/tex] = 41.22 mL

Molarity of [tex]KOH[/tex] = 0.1322 M

Number of moles of [tex]KOH[/tex]

[tex]n=\text{Molarity}\times \text{Volume of }KOH\\\Rightarrow n=0.1322\times 41.22\times 10^{-3}\\\Rightarrow n=0.005449284\ \text{mol}[/tex]

2 moles of [tex]KOH[/tex] reacts with 1 mole of [tex]H_2SO_4[/tex]

So,

[tex]0.005449284\ \text{mol}[/tex] of [tex]KOH[/tex] reacts with M mole of [tex]H_2SO_4[/tex]

[tex]M=\dfrac{0.005449284}{2}=0.002724642\ \text{mol}[/tex]

Volume of [tex]H_2SO_4=25\times 10^{-3}\ \text{L}[/tex]

Concentration of [tex]H_2SO_4[/tex] is

[tex]M=\dfrac{0.002724642}{25\times 10^{-3}}\\\Rightarrow M=0.10898568\approx 0.1090\ \text{M}[/tex]

The concentration of the unknown [tex]H_2SO_4[/tex] solution is [tex]0.1090\ \text{M}[/tex].

Answer:

Estoy triste, tuve que regalar a mi perro

Answer:

Freezing points for water with freezing mixtures based on salt and ice: Ammonium Nitrate - Chrushed Ice or Snow in Water 1 part Ammonium Nitrate - 0.94 parts Ice/water : temperature -4 o C 1 part Ammonium Nitrate - 1.20 parts Ice/water : temperature -14 o C

Explanation:

Mass of Hydrogen chloride : 4.672 g

Given

Reaction

Fe + 2HCl ⇒ FeCl2 + H2

3.56 g of Iron

Required

mass of Hydrogen chloride

Solution

mol of Iron (Ar = 56 g/mol) :

mol = mass : Ar

mol = 3.56 : 56

mol = 0.064

mol HCl from the equation :

= 2/1 x mol Fe

= 2/1 x 0.064

= 0.128

Mass HCl :

=mol x MW HCl

= 0.128 x 36.5

= 4.672 g

Answer:

A, chemical change

Explanation:

When marshmallows are toasted, a chemical change occurs. The sugar molecules in the marshmallow are being changed into carbon. Sugar can be changed into water molecules. When you toast marshmallows, the heat causes a chemical reaction producing water molecules which then evaporate, leaving the carbon behind.

Answer:

1.593 moles

Explanation:

Therefore, 1.593 moles are equal to 89.23 g of calcium oxide.

Answer:

9.64 × 10²³ molecules

Explanation:

Given data:

Mass of calcium oxide = 89.23 g

Number of molecules = ?

Solution:

First of all we will calculate the number of moles of calcium oxide.

Number of moles = mass/molar mass

Number of moles = 89.23 g/ 56.1 g/mol

Number of moles = 1.6 mol

Number of molecules;

1 mole contain 6.022 × 10²³ molecules

1.6 mol × 6.022 × 10²³ molecules / 1mol

9.64 × 10²³ molecules

The number 6.022 × 10²³ is called Avogadro number.

The oxidation number of  Sulphur = +2

General formula for determining Oxidation Numbers :

1. The number of oxidation of single element atoms = 0. Examples of Ar, Mg, Cu, Fe, N₂, O₂, etc. = 0

Group I : +1

Group II : +2

H in compound = +1, except metal hydride compounds (Hydrogen which binds I or II groups) oxidation number H = -1, for example, LiH, MgH₂, etc.

2. Oxidation number O in compound = -2, except OF2 = + 2 and in peroxide (Na₂O₂, BaO₂) = -1 and superoxide, for example KO₂ = -1/2.

3 The oxidation number in a non-filled compound = 0,

The total amount of oxidation in ion = ion charge, Example NO₃⁻ = -1

Sodium thiosulphate​ - Na₂S₂O₃

Oxidation number Na = +1 ⇒x2 = +2

Oxidation number O = -2 ⇒x3 = -6

Oxidation number Na₂S₂O₃ = 0

2.Na+2.S+3.O=0

2.+1+2.S+3.(-2)=0

2+2S-6=0

-4+2S=0

2S=4

S=+2

Answer:

K = [Ca²⁺] [OH¯]² / [Ca(OH)₂]

Explanation:

Equation for the reaction is given below:

Ca(OH)₂(s) —> Ca²⁺(aq) + 2OH¯(aq)

Equilibrium constant =?

Equilibrium constant (K) for a reaction is simply the ratio of the concentration of the products raised to their coefficient to the concentration of the reactants raised to their coefficient.

Thus, we can write the equilibrium constant (K) for the above reaction as follow:

Ca(OH)₂(s) —> Ca²⁺(aq) + 2OH¯(aq)

K = [Ca²⁺] [OH¯]² / [Ca(OH)₂]

Answer:

E = 7.11 × [tex]10^{-7}[/tex]  Cal

Explanation:

given data

efficiency = 25 %

solution

first we get here E by the power that is express as

p = [tex]\frac{E}{t}[/tex]     ...........1

E = p × t

E = 1 ×  2 × [tex]\frac{1hp}{746w} \times \frac{1hr}{3600 s}[/tex]  

E = 7.447 × [tex]10^{-7}[/tex] J

and

Ein is get by efficiency

Ein = [tex]\frac{Eout}{\eta }[/tex]        ..................2

Ein = [tex]\frac{7.447 \times 10^{-7}}{.25 }[/tex]

Ein = 29.788 × [tex]10^{-7}[/tex]  J

so required energy is

E = 29.788 × [tex]10^{-7}[/tex]  ×  [tex]\frac{1Cal}{4.184J}[/tex]

E = 7.11 × [tex]10^{-7}[/tex]  Cal

Answer:

Gravitational force between two objects depends on: a. The weight of the objects c. The mass of each object b. The distance between the objects d. Both b and c Please select the best answer from the choices provided A B C D

✓d

The  concentration (in M) of SO₂ in the wine : c. 3.9 x 10⁻³

Given

Reaction

SO2(aq) + 2H2O(l) + I2(aq) → 4H+ (aq) + 21- (aq) + SO42- (aq)

Required

The  concentration (in M) of SO2

Solution

Titration ⇒ mol SO₂ = mol iodine(I)

mol iodine :

=15.62 ml x 0.00501 M

=0.078256 mlmol

From equation, mol ratio of of SO₂ : I₂ = 1 : 1, so mol SO₂=0.078256

The concentration of SO₂(in 20 ml sample) :

M = n/V

M = 0.078256 mlmol/20 ml

M = 0.0039128

M = 3.9 x 10⁻³

Answer:

52.8 Liters

Explanation:

Gay-Lussacs law states that P1/T1 = P2/T2

if:

then:

45/298.1 = P2/328.1

P2 = 52.8

The new volume of the balloon is 52.8 Liters this can be calculated by using gas laws.

Charles law states the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature. It is given by

V₁/T₁ = V₂/T₂

What information do we have?

V₁ = 45 L

T₁ = 25 + 273.1 =298.1 K

T₂ = 55 + 273.1 = 328.1 K

To find:

V₂= ?

On substituting the values:

45/298.1 = V₂/328.1

V₂ = 52.8 L

Thus, the volume of the balloon is 52.8 liters.

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Answer:

A

Explanation:

a) C6H14, C8H18 – London-dispersion force

Since both substances have the same intermolecular force, the substances with the

larger molecular mass with have the higher boiling point. In this case, C8H18 will

have the higher boiling point.

b) C3H8 – London-dispersion force

CH3OCH3 –Dipole-dipole

The higher boiling point belongs to CH3OCH3 because is has the stronger

intermolecular force, dipole-dipole interaction.

c) CH3OH – Hydrogen bonding

CH3SH – Dipole-dipole interaction

Hydrogen bonding is the strongest intermolecular force, so CH3OH will have the

higher boiling point.

d) NH2NH2 – Hydrogen bonding

CH3CH3 – London-dispersion force

Hydrogen bonding is the strongest intermolecular force, so NH2NH2 will have the

higher boiling point.

The only intermolecular interaction present in the methane molecule is London dispersion forces.

The following points can be considered:

Therefore, the correct answer is D)CH4 that is methane.

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Answer:

Heat energy can be calculated by using the specific heat of a substance multiplying it to the mass of the sample and the

change in temperature. It is expressed as:

Energy = mCAT

Energy = 100 (0.90) (150 - 30)

Energy = 10800 J

Answer:

B: CaCO3 + 2HCl -> CaCl2 + H2CO3

Explanation:

Count how many elements they are in all molecules for the reactants and for the products.

Ca = 1 element

C = 1 element

O = 3 elements

H = 1 element

Cl = 1 element

Ca = 1 element

Cl = 2 elements

H = 2 elements

C = 1 element

O = 3 elements

To balance this equation, we need to add 1 more element of Chlorine and Hydrogen.  Therefore, we add a 2 to the coefficient of HCl for the reactants side.

Now let us try it.

Count how many elements they are in all molecules for the reactants and products.

Ca = 1 element

C = 1 element

O = 3 elements

H = 2 element

Cl = 2 element

Ca = 1 element

Cl = 2 elements

H = 2 elements

C = 1 element

O = 3 elements

All of the elements are balanced.

Hope it helped!

Answer:

3 half-lives 7. An isotope of Cesium (Cesium-137) has a half life of 30 years. If 1.0 mg of cesium-137 disintegrates over a period of 90 years, how many mg of cesium-137 would remain? of sodium-25 is 60 seconds? : 3 minutes t=601 = 3 half-lives 5.0mg ~ 2.5 mg + 1.25mg →) 625 mg.

Explanation:

Hope this helps

       where:

      [tex]N_{0}[/tex] = Initial quantity of the sample = 1.0g

       t = time in years of disintegration = 90 years

      [tex]t\frac{1}{2}[/tex] = Half life of cesium isotope = 30 years

      N(t) = Quantity of substance after disintegration = ?

N(t) =  [tex]1 ( \frac{1}{2})^ \frac{90}{30}[/tex]

N(t) =  [tex]1 (\frac{1}{2})^{3}[/tex]

N(t) = 0.125 grams

Therefore, the quantity of cesium-137 that would remain after disintegrating over a period of 90 years is 0.125 grams.

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