WIL GIVE BRAINLISEST PLEASE HELP SPEED ACCELERATION GRAPHS LABEL THE GRAPHS PLEASEEeeee
Answer:
Take the numbers and fill them in graph.
Plot time as X and speed as Y and afterward join then like a line graph.
Beasy is driving in his car to take care of some errands. The first errand has him
driving to a coffee shop 2 km East and 6 km North of his starting location. Once he
completes that errand, he drives to a thrift store which is 4 km East of the first errand.
What is the displacement of the car from the starting point, rounded to the nearest
km?
At this point in the story, Beasy has driven his car (2+6+4) = 12 km.
He is parked at the thrift store, (2+4) = 6 km East and 6 km North of his starting point.
As the crow flies, the thrift store is √(6km² + 6km²) in a straight line from the starting point.
That's √(72 km²) , which works out to 8.485 km . When rounded to the nearest whole km, he can phone up his wife and tell her he's "eight kilometers from home can you hear me now ?".
Displacement is a vector, so to answer the question completely, we also need to state its direction.
The angle from home to the thrift store, relative to East, is arctan(6km/6km).
That's 45 degrees.
The full displacement vector is 8.485 km Northeast.
From the question, Beasy drives 2km East and 6 km North. He then drives 4 km East of the first errand. An illustrative diagram is shown in the attachment below.
From the diagram S is the starting starting point, C is coffee shop and T is the thrift store.
The displacement of the car from the starting point is giving by /TS/ in the diagram. To calculate /TS/, consider the right-angled triangle TSQ, /TS/ is the hypotenuse.
From The Pythagorean theorem, in a right-angled triangle, the square of the longest side (hypotenuse) equals sum of the squares of the other two sides.
That is,
/TS/² = /SQ/² + /TQ/²
But /TQ/ = /CP/ = 6km
and /SQ/ = /SP/ + /PQ/
/SP/ = 2 km, /PQ/ = 4 km
∴ /SQ/ = 2 km + 4 km
/SQ/ = 6 km
Hence,
/TS/² = 6² + 6²
/TS/² = 36 + 36
/TS/² = 72
/TS/ = [tex]\sqrt{72}[/tex]
/TS/ = 8.485 km
/TS/ ≅ 8 km ( to the nearest km)
Hence, the displacement of the car from the starting point rounded to the nearest km is 8 km.
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When deciding antenna types, why might the use of an omnidirectional antenna be inadvisable?
Answer:
Omnidirectional antennas are inadvisable to be used because when oriented vertically they radiate radio power equally in all horizontal directions, but heir radio power varies with the angle to the axis, reducing to zero at the axis.
Explanation:
Omnidirectional antennas radiates equal radio power in all directions perpendicular to an axis, with power varying with the elevation angle. This means that their power declines to zero on the axis. This is unlike the isotropic antennas that radiates equal power in all directions, without any reduction in radio power with angle to the axis. Omnidirectional antennas are mostly used for radio broadcasting antennas in mobile devices that use radio such as cell phones, FM radios, walkie-talkies, wireless computer networks etc.
Which statement is supported by the motion map?
The train traveled south and then north.
The train moved at a velocity of 75 mph north.
The train had a greater velocity when it moved away from the origin.
The train stopped for 3 seconds.
Answer:
The train stopped for 3 seconds.
Explanation:
D on edge
Which structure is represented by letter B?
Choose 1 answer:
(Choice A) A Cytosol
(Choice B) B Cell membrane
(Choice C) C Ribosome
(Choice D) D Cell wall
Answer: A Cytosol
Explanation: Jelly - like fluid that fills the space between cell organelles. Hoped This Helped :) Have a blessed day.
The cytoskeleton, which gives a cell its structure, allows organelles to move inside the cell, and provides a method by which the cell itself can move, is an ordered framework of fibrous molecules found in the cytoplasm. Thus, option A is correct.
What is the main function of cytosol in the cell?The fluid that fills cells is called cytosol. In this water-based solution, organelles, proteins, and other cell components float. Any cell's cytosol is a sophisticated solution whose characteristics allow for the performance of life's essential processes.
The cytoplasm houses all the organelles found in eukaryotic cells, including the nucleus, endoplasmic reticulum, and mitochondria.The portion of the cytoplasm that is not contained in an organelle is known as the cytosol.
Therefore, Although the cytoplasm may not seem to have any shape or organization, it is actually quite well-organized.
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A dolphin maintains a constant speed of 2.0 m/s for 24 s while swimming in a straight line. It then reverses direction and returns to its starting point in 8 s. Its average speed and average velocity for the entire trip are
Answer:
Average speed 3m/sAverage velocity is 4m/s
Explanation:
In this problem, we are going to solve for the average speed and average velocity for the entrire trip made by the dolphin.
Given data
speed v= 2 m/s
time t= 24s
the distance travelled by the dolphin is
speed= distance/time
distance= speed*time
distance= 2*24
distance= 48m
now the dolpine made a reverse and covered this 48m in 8s to return to it initial position
the speed it took is
speed= distance/time
speed= 48/8
speed= 6m/s
It average speed is the total distance divided by the total time taken
average speed= (48+48)/(24+8)= 96/32= 3m/s
average speed= 3 m/s
it average velocity is the sum of the initial and final velocity is divided by 2 to find the average
(2+6)/2= 8/2= 4m/s
average velocity is 4m/s
A brick has a mass of 562 g and a volume of 43 cm3. What is the density?
Answer:
13.069 g/cm^3
Explanation:
to get density, simply divide the mass by the volume. Your equation would look like this; p=562/43
'P' represents density in this equation. Never forget to add your units!
Hope this helps!
The image shows the pH value of some common substances. Which statement is true?
A-Pure water is acidic
B-Pure water is basic
C-Pure water is both acidic and basic
D-Pure water is neither acidic nor basic
HELP PLEASE . SCIENCE
What’s the difference between atoms and molecules in a substance?
Answer:
Atoms are single neutral particles.
example: Ne, O
Molecules are neutral particles made of two or more atoms bonded together.
example:O2,HCl
Answer:
Atoms are single particles while molecules are particles made of two or more atoms bonded together.
Explanation:
what is the difference between an ideal machine and a practical machine
Answer:
Ideal machines are said to have parts which are weightless , frictionless and strings if any are inextensible. Practical machines have parts which have weights, friction and it causes some loss of work done.
Explanation:
Answer: Ideal machines are said to have parts which are weightless , frictionless and strings if any are inextensible. Practical machines have parts which have weights, friction and it causes some loss of work done.
Explanation:
A mass of gas occupies 20 cm3 at 5 degrees Celcius and 760 mm Hg pressure. What is its volume at 30 degrees Celcius and 800 mm Hg pressure?
Answer:
20.7 cm³
Explanation:
From the question given above, the following data were obtained:
Initial volume (V1) = 20 cm³
Initial temperature (T1) = 5 °C
Initial pressure (P1) = 760 mm Hg
Final temperature (T2) = 30 °C
Final pressure (P2) = 800 mm Hg
Final volume (V2) =?
Next we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:
Temperature (K) = Temperature (°C) + 273
Initial temperature (T1) = 5 °C
Initial temperature (T1) = 5 °C + 273 = 278 K.
Final temperature (T2) = 30 °C
Final temperature (T2) = 30 °C + 273 = 303 K.
Finally, we shall determine the new volume of the gas as follow:
Initial volume (V1) = 20 cm³
Initial temperature (T1) = 278 K
Initial pressure (P1) = 760 mm Hg
Final temperature (T2) = 303 K
Final pressure (P2) = 800 mm Hg
Final volume (V2) =?
P1V1/T1 = P2V2/T2
760 × 20 /278 = 800 × V2/303
Cross multiply
278 × 800 × V2 = 760 × 20 × 303
Divide both side by 278 × 800
V2 = (760 × 20 × 303) / (278 × 800)
V2 = 20.7 cm³
Therefore, the new volume of the gas is 20.7 cm³
10.What is the Kinetic Energy of a 150 kg object that is moving with a speed
of 15 m/s? (7b)
In which block of the periodic table is uradium (U) found?
s block
d block
р
block
f block
Answer:
f block on edge 2020
Explanation:
hope this helps:)
What is the closed physical system?
A. Non of the answers are true
B. A system where matter and energy can leave but not enter the system
C.a system where matter and energy can leave but not enter the system
D. A system where matter and energy can not enter or leave the system
Which are functions of the endoplasmic reticulum (ER)?
Choose 2 answers:
A. DNA storage
B. Protein modification
C. Lipid synthesis
D. ATP production
Answer:
a. DNA storage
Explanation:
3. A rock has a volume of 6 cm3 and a mass of 24g. What is the density of the rock?
Explanation:
Assume that the rock has a constant density,
then the density = volume/mass = 0.25g/cm^3.
Answer:
4 g/cm^3
Explanation:
Density can be found by dividing the mass by the volume.
d=m/v
We know that the mass of the rock is 24 gram. We also know the volume of the rock is 6 cubic centimeters.
m=24 g
v= 6 cm^3
Substitute the values into the formula and divide.
d= 24 g / 6 cm^3
d= 4 g/cm^3
The density of the rock is 4 grams per cubic centimeter.
your alpaca is walking down the road at 4 m/s. how far does it go in 45 seconds?
Answer:
180
Explanation:
4m/s x 45s=180m
The diagram below shows a 1.5 kilogram kitten jumping from the top of a 1.80 meter high refrigerator to a 0.90 meter high
counter.
Refrigerator
Counter
CO
The kitten's gravitational potential energy on top of the refrigerator is greater, but what is the kitten's gravitational
potential energy on top of the counter? Assume gravity as 10, if needed.
Answer:
E = 27 J
Explanation:
It is given that,
Mass of a kitten is 1.5 kg
Initially, it was at a height of 1.8 m refrigerator and finally jumps to a 0.9 m height counter.
We need to find the kitten's gravitational potential energy on top of the counter. Potential energy is possessed due to the position of an object. It can be given by :
[tex]E=mgh[/tex]
g is acceleration due to gravity
[tex]E=1.5\ kg\times 10\ m/s^2\times 1.8\ m\\E=27\ J[/tex]
So, the kitten's gravitational potential energy on top of the counter is 27 J.
what is base rule of rounding off
why aren't two hydrogen atoms bonded together considered a compound explain.
Answer: Because a compound is formed by at least two elements, and here we have only one.
Explanation:
A compound is defined as:
"A substance that is formed when two or more elements are chemical bonded together"
And in this case, we have two hydrogen atoms bonded together, so we have the bond, but there is only one element, and we need to have at least two elements to have a compound.
Two hydrogen atoms bonded together are not considered a compound.
Compounds:A compound is formed when two are more different elements form a chemical bond with each other and make a substance.
For any substance to be categorized as a compound it is necessary that it contains at least two different elements.
A substance that is formed by the chemical combination or bonding of the atoms of the same element is not considered a compound.
In the given case we have two hydrogen atoms bonded together, which is very clear that the substance contains the atoms of the same element bonded together.
Therefore it can not be considered a compound.
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An object is released from rest near a planet’s surface. A graph of the acceleration as a function of time for the object is shown for the 4 s after the object is released. The positive direction is considered to be upward. What is the displacement of the object after 2 s?
Answer:
the body has descended a height (4a)
Explanation:
This exercise should use the acceleration given in the graph, but unfortunately the graph is not loaded, but we can build it, using the law of universal gravitation and the fact that you indicate that the movement is near the surface of the planet
F = m a
f
orce is gravitational force
G M m / r² = m a
a = G M / r²
where G is the universal constant of gravitation, M the mass planet and r the distance from the center of the planet of radius R to the body, if we measure the height of the body from the surface of the planet (y), we can write
r = R + y
for which
a = G M/R² (1+ y/R)⁻²
if we use y«R we can expand the function in series
a = (G M /R²) (1 -2 y/R - 2 (-2-1) /2! y² / R² +…)
as the height is small we can neglect the quadratic term and in many cases even the linear term, for this exercise we will remain only constant therefore the acceleration is constant
a = G M / R²
from this moment we can use the relations of motion with constant acceleration for the exercise
a) they ask us for the position for t = 2s
y = y₀ + v₀ t - a t²
as the body is released v₀ = 0
y-y₀ = - a t²
y-y₀ = - a 2²
y-y₀ = - a 4
therefore
therefore the body has descended a height (4a) where a is the acceleration of the planet's gravity
A spaceship is flying through space at a very high velocity .The astronaut shuts the engines off the spaceship will
Answer:
The astronauts will simply have to fire the rocket engines again to keep moving. The spacecraft will keep coasting at the same speed and in the same direction. The spacecraft will slow down until it comes to a complete stop. ... Its speed will be constant except for very slow changes that are part of its orbital motion.
Explanation:
The x-component is 8 m/s east; the y-component is 14.5 m/s North. (a) What is the value of the resultant vector? (b) What is the angle of the resultant vector?
Explanation:
Given that,
The x-component is 8 m/s east and y-component is 14.5 m/s North.
(a) As both x and y components are perpendicular to each other. Their resultant is given by :
[tex]R=\sqrt{x^2+y^2} \\\\R=\sqrt{(8)^2+(14.5)^2} \\\\R=16.56\ m/s[/tex]
(b) Let [tex]\theta[/tex] is the resultant vector. So,
[tex]\tan\theta=\dfrac{y}{x}\\\\\theta=\tan^{-1}(\dfrac{y}{x})\\\\\theta=\tan^{-1}(\dfrac{14.5}{8})\\\\\theta=61.11^{\circ}[/tex]
Hence, the resultant is 16.56 m/s and the angle of the resultant vector is 61.11 degrees.
A box of paper is labeled 24lb paper. This means that 500 sheets (counted number) of paper size 17in x 22in weighs 24 pounds (The paper industry in the US has not switched over to metric.). On earth, 1.0lb, using the standard acceleration of gravity, corresponds to 453.6g. Calculate the mass of a single piece of paper that measures 21.59cm x 27.94cm
Answer:
The mass of a single paper is approximately 0.047 lb/paper which in SI Units is approximately 21.77 g/paper
Explanation:
The given information on the size and the weight of paper are;
The mass of a box of 500 sheets of paper = 24 lb
The number of sheets in the paper = 500 sheets
The dimensions of the paper = 17 in. × 22 in., which is equivalent to 43.18 cm × 55.88 cm
The mass of a single paper = The mass of the box of paper/(The number of sheets of paper present in the box)
The mass of a single paper = 24 lb/500 = 0.047 lb/paper
Given that 1 lb = 453.6 g, we have;
0.047 lb/paper = 0.047 lb/paper×453.6 g/(lb) = 21.77 g/paper
The mass of a single paper = 0.047 lb/paper = 21.77 g/paper.
Answer:
5.349g
Explanation:
The other post forgot about the differing answer. They wanted the answer for 21.59cm*27.94cm. when they get that 0.047=43.18cm*55.88cm we can set a ratio;
0.047/43.18*55.88=X/21.59*27.94=0.01179
then we do the same;
0.01179lb(453.6g/1lb)=5.349
(*the number is bigger but we have 4 sig figs*)
Which of the following is NOT a piece of evidence for the Big Bang Theory?
Ratio of Hydrogen and Helium to other elements
Expanding Universe
Black Holes
Cosmic Microwave Background Radiation
um the answer is A
np :3 i hope this is right
Same amount of force is acting on car and bus.If the ratio of the bus and car 25:1 calculate the ratio of the acceleration produced in the car to the acceleration produced in the bus
Answer:
1:25
Explanation:
The force acting on an object is given by :
F = ma ...(1)
m is mass and a is acceleration
It is given that the ratio of force acting on the bus and car 25:1 i.e. [tex]\dfrac{F_1}{F_2}=\dfrac{25}{1}[/tex], 1 is for bus and 2 is for car.
We need to find the ratio of the acceleration produced in the car to the acceleration produced in the bus. From equation (1),
[tex]\dfrac{F_1}{F_2}=\dfrac{a_1}{a_2}[/tex]
[tex]\dfrac{a_2}{a_1}=?[/tex]
[tex]\dfrac{F_1}{F_2}=\dfrac{1}{25}[/tex]
So, the ratio is 1:25.
If I drop a paper clip from rest and it falls freely until it hits the ground with a speed of 30 m/s. How long is the ball in free fall?
Answer:
3.06sExplanation:
If I drop a paper clip from rest and it falls freely until it hits the ground with a speed of 30 m/s,we ae to find the time taken for the ball to drop. To do that we will use the equation of motion v = u + gt
v is the final velocity = 30m/s
u is the initial velocity = 0m/s (the object drops from rest)
g is the acceleration due to gravity = 9.81m/s²
time is the time taken
Substituting the given parameters into the formula;
30 = 0 + (9.81)t
30 = 9.81t
t = 30/9.81
t = 3.06secs
Hence it will take the object 3.06secs in free fall
Will somebody plz help
Answer:
very complex
Explanation:
The answer is D very complex
An object traveling at a constant 20m/sec in a circular path is changing its:
My answer to the question is Velocity.