A 5 kg bowling ball with a velocity of +10 m/s collides with a stationary 2 kg bowling pin. If the ball's final velocity is +8 m/s, what is the pin's final velocity?

a 5 m/s
b 2.5 m/s
c 10 m/s
d 5.2 m/s

Answer:

33 Inches

Explanation:

The movement of the ant is sketched in the attached image. The ant moved from the 19-inch mark to 27-inch mark covering a distance of 13 Inches (27 - 19). Finally, it moved from the 27-inch mark to 7-inch mark covering a distance of 20 Inches (27 - 7).

Total Distance covered = 13 + 20 = 33 Inches.

Hence, the total distance the ant traveled is 33 Inches.

Answer:

W = 1750 J

Explanation:

It is given that,

Weight of a computer, F = 50 N

A student wants to keep it on the 5th floor which is 35 meters up.

We need to find the work done by her to drag her computer up the stairs. Let it is W. Using the formula of work as follows :

W = F d

Put all the values,

W = 50 N × 35 m

W = 1750 J

So, 1750 J of work is done by her to drag the computer up the stairs.

Answer:

YESS well it is partly nessary but it depends on the situation

Explanation:

Answer:

Weathering, erosion, and deposistion are necessary processes in the rock cycle because:

Explanation:

First, start with igneous rocks. magma erupts (Extrusive igneous rocks) or solidifies in the sub-surface of the earth (Intrusive igneous rock). when they are exposed Weathering and erosion occur which is a slow breakdown of rock through the wind, water, or other processes. The weathered pieces (sediments) move to other places by wind or water and get deposited someplace else. When there are enough sediments and there is overburden pressure on these sediments, they become a sedimentary rock. Due to overburden pressure, they become metamorphic rocks. now the thing to understand here is that when metamorphic rocks are exposed, they too undergo weathering and erosion and their pieces also become sedimentary rocks.

Answer:

v₁ = 0.375 m / s ,   x = 0.335 m

Explanation:

Let's analyze this interesting exercise, the block moves and has a friction force with the tile, we assume that the speed of the block is constant, so the friction force opposes the block movement. For the only force that acts (action and reaction) this friction force exerted by the block that is in the direction of movement of the tile.

We can also see that the isolated system formed by the block and the tile will reach a stable speed where friction cannot give the system more energy, this speed can be found by treating the system with the conservation of linear momentum.

initial moment. Right at the start of the movement

       p₀ = m v₀ + 0

final moment. Just when it comes to equilibrium

      [tex]p_{f}[/tex] = (m + M) v₁

how the forces are internal

       p₀ =p_{f}

       m v₀ = (m + M) v₁

       v₁ = m /m+M    v₀

let's calculate

       v₁ = 0.4 /(0.4 + 2.8)  3

       v₁ = 0.375 m / s

Let's apply Newton's second law to the Block, to find the friction force

Y axis

       N - W = 0

       N = W

       N = m g

where m is the mass of the block

the friction force has the formula

      fr = μ N

      fr = μ m g

We apply Newton's second law to slab    

X axis

       fr = M a

where M is the mass of the slab

       μ m g = M a

       a = μ g m / M

let's calculate

       a = 0.15  9.8  0.4 / 2.8

       a = 0.21 m / s²

With kinematics we can find the position

       v²= v₀²+2 a x

as the slab is initially at rest, its initial velocity is zero

       v² = 2 a x

       x = v2 / 2a

let's calculate

        x = 0.375²/2 0.21

        x = 0.335 m

Answer:

the answer is a time your welcome

Answer:

(1)

Explanation:

A.)

Water is the name of the pure substance H₂O

B.)

Hydrogen and Oxygen are the compound of water

C.)

Yes, we can

D.)

This process known as Electrolysis

Answer:

Explanatio

Increasing the speed of the relative motion between the coil and the magnet – If the same coil of wire passed through the same magnetic field but its speed or velocity is increased, the wire will cut the lines of flux at a faster rate so more induced emf would be produced. 3)n:

Answer:

Average velocity = 5.9 km/ hr (or 1.64 m/s).

Explanation:

Velocity = [tex]\frac{displacement}{time}[/tex]

It is a vector quantity and has an SI unit of m/s.

Displacement = [tex]\sqrt{x^{2} + y^{2} }[/tex]

x = 5 km east

y = 6 km north + 4 km north

  = 10 km north

So that,

Displacement = [tex]\sqrt{5^{2} + 10^{2} }[/tex]

                       = [tex]\sqrt{25 + 100}[/tex]

                       = [tex]\sqrt{125}[/tex]

                       = 11.1803

Displacement = 11.18 km = 11180 m

Time = 1.9 hr = 6840 seconds

Average velocity = [tex]\frac{11.180}{1.9}[/tex]

             = 5.8842

Average velocity = 5.9 km/ hr

The average velocity is 5.9 km/ hr (or 1.64 m/s).

Answer:

ΔP =  20000 N s

Explanation:

To solve this problem we use the relation between momentum and moment

         I = Δp

let's calculate the momentum

         I = ∫F dt

if we use the average force

       I = F t

       I = 10000 2

       I = 20000 N s

therefore with the first equation

        ΔP = I = 20000 N s

Answer:

Solar energy is renewable.

Explanation:

If something is renewable, it is generated faster than it can be reasonably used or won't run out for longer than it would be used. Solar falls into the latter category. Using solar panels won't deplete the sun and the sun will likely be around for much longer than we will.

Answer:

The momentum of the car is 3190.74 kgm/s

Explanation:

Given;

weight of the car, w = 1,356 N

velocity of the car, v = 83 km/h = 23.06 m/s

The mass of the car is given by;

m = w/g

where;

g is acceleration due to gravity = 9.8 m/s²

m = 1356 / 9.8

m = 138.367 kg

The momentum of this car is given by;

P = mv

P = (138.367 x 23.06)

P = 3190.74 kgm/s

Therefore, the momentum of the car is 3190.74 kgm/s

Answer:

0.585V

Explanation:

Given that:

B = 3.00 × 10-5 T

l = 75.0 m

v = 260 m/s

From Blv = emf between the wing tips

= 3.00 × 10-5 T × 75×260

= 117/200

= 0.585V

Hence, the emf between the wing tips is 0.585V

Answer:

s = 6.25 10⁻²² m

Explanation:

Polarizability is the separation of electric charges in a structure, in the case of the atom it is the result of the separation of positive charges in the nucleus and the electrons in their orbits, macroscopically it is approximated by

                p = q s

               s = p / q

let's calculate

              s = 1 10⁻⁴⁰ / 1.6 10⁻¹⁹

              s = 0.625 10⁻²¹ m

              s = 6.25 10⁻²² m

We see that the result is much smaller than the size of the atom, therefore this simplistic model cannot be taken to an atomic scale.

Answer:

$30

Explanation:

Given that,

Power of a water heater, P = 2000 Watts

It is on for a total of 150 hours a month.

2000 Watts = 2 kW

Time, t = 150 hours

Energy used by the water heater is given by :

[tex]E=P\times t\\\\E=2\ kW\times 150\ h\\\\E=300\ kWh[/tex]

It is also mentioned that the cost is 10 cents per kWhr.

Since, $1 = 100 cents

10 cents = $0.1

So, the total cost for the month is :

Cost = 300 × 0.1

Cost = $30

So, the required cost is $30.

Answer:

W = 0.49 N

τ = 0.4851 Nm

Force

Explanation:

The weight force can be found as:

W = mg

W = (0.05 kg)(9.8 m/s²)

W = 0.49 N

The torque about the pivot can be found as:

τ = W*d

where,

τ = torque

d = distance between weight and pivot = 99 cm = 0.99 m

Therefore,

τ = (0.49 N)(0.99 m)

τ = 0.4851 Nm

The pivot exerts a  FORCE on the meter stick because the pivot applies force normally over the stick and has a zero distance from stick.

Answer:

10 seconds

Explanation:

Answer:

You will be very glad to know that my preparation for HSC examination is very good. I have prepared myself for the HSC Examination 2015. I am confident that I will obtain very good marks in the examination. I have revised them several times and I am hopeful of obtaining distinction marks in all the subjects.

Explanation:

This is from Brainly hope this person helped you

Answer:easter

Explanation:

Answer:

Easter

Explanation:

did it on edge, and searched it up

Answer:

The resistance of a wire decreases with increasing thickness.

Explanation:

Hope this helped!

Answer: C it allows electrons to flow more easily

Explanation:i got it right i hope this helps you

Answer:

V = 6.65 [volt]

Explanation:

We must first find the power generated, power is defined as the amount of energy consumed or generated in a given time.

[tex]P=\frac{E}{t}[/tex]

where:

P = power [w]

E = energy = 40 [J]

t = time = 30 [s]

[tex]P =40/30\\P = 1.33[w][/tex]

Now we can calculate the voltage or potential drop by means of the power, the power is calculated by means of the product of the voltage by the current.

[tex]P =V*I[/tex]

where:

V = voltage [volts]

I = current = 200mA = 0.2 [A]

[tex]V = P/I\\V = 1.33/0.2\\V = 6.65 [Volt][/tex]

Answer:

Weight = normal force = 24.5 N

Explanation:

Given that,

Mass of a dog, m = 2.5 kg

We need to find its weight and the normal force that it feels.

The weight of an object is given by :

W = mg

Where g is the acceleration due to gravity

[tex]W=2.5\times 9.8\\\\=24.5\ N[/tex]

The normal force is balanced by the weight of an object. So,

Weight = normal force = 24.5 N

Answer:

x' = 0.085 m = 8.5 cm

Explanation:

The law of conservation of energy says that:

Potential Energy Stored in Spring = Loss in Gravitational Potential Energy of Block

(1/2)kΔx² = mgh

where,

k = stiffness of spring = 1070 N/m

Δx = change in length of spring = ?

m = mass of block = 0.5 kg

g = 9.8 m/s²

h = height of block above spring = 0.6 m - 0.15 m = 0.45 m

Therefore,

(1/2)(1070 N/m)Δx² = (0.5 kg)(9.8 m/s²)(0.45 m)

Δx = √[2(2.205 Nm)/(1070 N/m)]

Δx = 0.064 m

but,

Δx = x - x' = 0.15 m - x' = 0.064 m

x' = 0.15 m - 0.064 m

x' = 0.085 m = 8.5 cm

Answer:

I found "As nouns the difference between resultant and equilibrium is that resultant is anything that results from something else; an outcome while equilibrium is the condition of a system in which competing influences are balanced, resulting in no net change. is following as a result or consequence of something."

Explanation:

A spring balance measures the weight of an object by opposing the force of gravity acting with force of an extending spring. May be used to determine mass as well as weight by recalibrating the scale. Some spring balances are available in gram or kilogram markings and are used to measure the mass of an object. Spring balances consist of a cylindrical tube with a spring inside. One end (at the top) is fixed to an adjuster which can be used to calibrate the device. The other end is attached to a hook on which you can hang masses etc.

Answer:

a.  (VL)R/ωL[1 - cos[ωt]]  = (10.84 V)[1 - cos[(487rad/s)t]]

b. 1.084 mV

Explanation:

a. Since it is a series circuit, the current in the inductor is the same as the current in the resistor.

Now, the voltage across the inductor vL = -Ldi/dt.

So, the current, i = -1/L∫vLdt.

Now, vL = −(12.0V)sin[(487rad/s)t] and L = 0.200 H

Substituting these into i, we have

i = -1/L∫vLdt

= -1/0.200H∫[−(12.0V)sin[(487rad/s)t]]dt.

= -[−(12.0V)]/0.200H∫[sin[(487rad/s)t]]dt.

= 60V/H∫[sin[(487rad/s)t]]dt

Integrating i, we have

i = 60V/H ÷ [(487rad/s)[-cos[(487rad/s)t]] + C

at t = 0, i(0) = 0

0 = 60V/H ÷ [(487rad/s)[-cos[(487rad/s)× 0]] + C

0 = 60V/H ÷ [(487rad/s)[-cos[0]] + C

0 = 60V/H ÷ [(487rad/s)[-1]+ C

C = 60V/H ÷ [(487rad/s)

So, i = 60V/H ÷ [(487rad/s)[-cos[(487rad/s)t]] + 60V/H ÷ [(487rad/s)

i =  60V/H ÷ [(487rad/s)[1 - cos[(487rad/s)t]]

i = (0.123A)[1 - cos[(487rad/s)t]] = VL/ωL[1 - cos[ωt]] where ω = 487rad/s and VL = 12.0 V and L = 0.200 H

So, the voltage across the resistor vR = iR where R = resistance of resistor = 88.0 Ω

So, vR = iR = VL/ωL[1 - cos[ωt]] × R = (VL)R/ωL[1 - cos[ωt]]

=  (0.123A)[1 - cos[(487rad/s)t]] × 88.0 Ω

= (10.84 V)[1 - cos[(487rad/s)t]]

b. vR at t = 2.00 ms = 0.002 s

So, vR = (10.84 V)[1 - cos[(487rad/s)(0.002)]]

= (10.84 V)[1 - cos[0.974]]

= (10.84 V)[1 - 0.9999]

= (10.84 V)(0.0001)

= 0.001084

= 1.084 mV

Answer:

yes

Explanation:

people still skateboard that is an easy question

Answer:

Approximately [tex]35.2\; \rm m[/tex].

Explanation:

Given:

Initial velocity: [tex]u = 13\; \rm m \cdot s^{-1}[/tex].

Acceleration: [tex]a = -2.40\; \rm m \cdot s^{-2}[/tex] (negative because the car is slowing down.)

Implied:

Final velocity: [tex]v = 0\; \rm m \cdot s^{-1}[/tex] (because the car would come to a stop.)

Required:

Displacement, [tex]x[/tex].

Not required:

Time taken, [tex]t[/tex].

Because the time taken for this car to come to a full stop is not required, apply the SUVAT equation that does not involve time:

[tex]\begin{aligned} x &= \frac{v^2 - u^2}{2\, a} \\ &= \frac{{\left(0\; \rm m \cdot s^{-1}\right)}^2 - {\left(13\; \rm m \cdot s^{-1}\right)}^2}{2\times \left(-2.40\; \rm m\cdot s^{-2}\right)} \approx 35.2\; \rm m \end{aligned}[/tex].

In other words, this car would travel approximately [tex]35.2\; \rm m[/tex] before coming to a stop.