Consider a circuit element, with terminals a and b, that has vab= -12V and iab= 3A. Over a period of 2 seconds, how much charge moves through the element? If electrons carry the charge, which terminal do they enter? How much energy is transferred? Is it delivered to the element or taken from it?

Answers

Answer 1

Answer:

a) 6 coulombs

b) The electrons carrying the charge will enter at point b with respect to element and this is because electrons follow in opposite direction of current

c) = -72 joules

Energy is taken from element

Explanation:

Given data:

V ab = -12 v

I ab = 3A

period ( t ) = 2 seconds

a) determine how much charge moves through the element

q = I * t

  = 3 * 2 = 6 coulombs

b) The electrons carrying the charge will enter at point b with respect to element and this is because electrons follow in opposite direction of current

c) determine how much energy is transferred

= Vab * Iab * t

= -12 * 3 * 2

= -72 joules

Energy is taken from element

Consider A Circuit Element, With Terminals A And B, That Has Vab= -12V And Iab= 3A. Over A Period Of

Related Questions

Products exit a combustor at a rate of 100 kg/sec, and the air-fuel ratio is 9. Determine the air flow rate. a. 9 kg/sec b. 90 kg/sec c. 100 kg/sec d. 10 kg/sec

Answers

Answer: the air flow rate a is 90 kg/sec; Option b) 90 kg/sec is the correct answer

Explanation:

Given that;

product of combustor flow rate m = 100 kg/s

air-fuel = 9

Airflow rate = ?

⇒We know that in the combustor, air fuel are mixed and then ignited,

⇒air fuel products are exited at the combustor

let air and fuel be a and b respectively

⇒ a + b = 100 kg/sec ----- let this be equation 1

now

⇒ air / fuel = 9

a / b = 9

a = 9b -----------let this be equation 2

now input a = 9b in equation 1

9b + b = 100 kg/sec

10b = 100 kg/sec

b = 10 kg/sec

we know that

a = 9b

so a = 9 × 10 = 90 kg/sec

Therefore the air flow rate a is 90 kg/sec

What is the basic molecular mechanism for polymer plasticity, and how does it differ from that of ductile crystalline metals?

Answers

Answer:

In Crystalline metals or materials, plasticity is examined from the perspective of the motion of linear defects or dislocations within the polymer chains.

Explanation:

When a temperature range below and near the glass transition temperature is reached, there is warping or contortion of structureless or malformed polymers. This warping happens as the polymer chains move over one another.

Unlike elasticity when requires or enables an object to resume its original dimensions, ductility is the quality of an element or material to change form albeit permanently.

Cheers

Calculate the molar volume of ammonia at 92oC and 310 bar. What phase is the ammonia in?

Answers

Answer:

The ammonia is still in the gas phase

Explanation:

Given that 1 bar is approximately = 1 atm

From;

PV=nRT

P= 310 atm

V= the unknown

n= 1

R = 0.082atm LK-1mol-1

T = 92oC + 273 = 365 K

V= nRT/P

V= 1 * 0.082 * 365/310

V = 0.0965 L = 96.5 mL

molar mass of NH3 = 17 g/mol

Molar density of NH3 = 17g/ 96.5mL = 0.176g/mL

The ammonia is still in the gas phase

How much energy in joule is added to a 12 g of sample of aluminum (c=0.897 J/g ◦C) to raise the temperature from 20 ◦C to 45 ◦C?

Answers

Answer:

269.1J

Explanation:

m = 12g

c = 0.897J/g°C

∆T = 45 - 20 = 25°C

H = mc∆T = 12 × 0.897 × 27 = 269.1J

Contrast the electron and hole drift velocities through a 10 um (micro meter) layer of intrinsic silicon across which a voltage of 5V is imposed. Let up = 480cm2/Vs and un=1350cm2/Vs.

Answers

Answer:

Explanation:

Since we are considering electron and hole drift velocities, then electric field E will have to be taken into consideration as well.

Where E = V/d...... 1

Drift velocity (u) = -μE. For electron.... 2

Drift velocity (v) = μE. For hole...... 3

Given that : V = 5V and d = 10 um (micro meter)

From equation 1

E = V/d

E = 5V/10×10^-4cm

E = 5V ÷1/1000

E = 5×1000

E = 5000v/cm

From equation 2

Un = -μE.

Un = - 1350cm^2/vs × 5000

= -6750000cm/s

From equation 3

Vp = μE

= 480cm^2/vs × 5000

= 2400000cm/s

Since it was stated in the question that we should contrast between hole drift and electron drift.

6750000/2400000

= 2.8125

Hence the electron drift velocity is 2.8 times that of hole drift velocity indicating that the speed of the electron through the silicon was faster.

People tend to self-disclose to others that are in age, social status, religion, and personality.

Answers

Answer:people tend to do this when they are in a different environment they lose something or just have something going on in their life

Explanation:

How would you expect an increase in the austenite grain size to affect the hardenability of a steel alloy? Why?

Answers

Answer:

The hardenability increases with increasing austenite grain size, because the grain boundary area is decreasing. This means that the sites for the nucleation of ferrite and pearlite are being reduced in number, with the result that these transformations are slowed down, and the hardenability is therefore increased.

what substance does light travel through before putting water in the cup

Answers

Bend surface in water! Hopefully this helps, I looked it up!

Solar energy stored in large bodies of water, called solar ponds, is being used to generate electricity. If such a solar power plant has an efficiency of 4.5 percent and a net power output of 150 kW, determine the average value of the required solar energy collection rate, in Btu/h.

Answers

Answer: 1.137*10^7 Btu/h.

Explanation:

Given data:

Efficiency of the plant = 4.5percent

Net power output of the plant = 150kw

Solution:

The required collection rate

QH = W/n

= 150/0.045 * 0.94782/ 1 /60 */60 Btu/h.

= 3333.333 *3412.152Btu/h.

= 11373840 Btu/h

= 1.137*10^7 Btu/h.

Calculate the Lee for the same wing if we increase the span to 0.245 m. By increasing the span we also increase the glider weight to 0.0523

Answers

Answer:

0.21

Explanation:

This would have been a fairly easy one, except for that the first part of the question is missing, and as such, I'd assume a value.

We need to use chord, so, I'm assuming the length of the chord to be 0.045 m

The Area is given by the formula

Area = span * chord

Area = 0.245 * 0.045

Area = 0.011 m²

This area gotten, is what we then divide the glider weight by to get our answer.

Lee = area / weight

Lee = 0.011 / 0.0523

Lee = 0.21

Therefore, using the values of the chord I'd assumed, the Lee of the same wing is 0.21

Answer: 0.2108

Explanation:got it correct

A production line manufactures 10-liter gasoline cans with a volume tolerance of up to 5%. The probability that any one is out of tolerance is 0.03. If five cans are selected at random. a) What is the probability that they are all out of tolerance? b) What is the probability that exactly two are out of tolerance?

Answers

Answer:

In the case of the production Line, we know that,

No of gasoline cans = 5

probability that 1st can is out of tolerance = 0.03

probability that 2nd can is out of tolerance = 0.03

.

.

probability that the 5th can is out of tolerance = 0.03

Therefore,

probability of 1st can out of tolerance + probability of 1st can not out of tolerance = 1

Probability of 1st can not out of tolerance = 1 -- 0.03 = 0.97

probability of 2nd can not out of tolerance = 0.97

.

.

probability of 5th can not out of tolerance = 0.97

Question A:

Probability that they are all out of tolerance

= P(1st can out of tolerance) * P(2nd can out of tolerance) * P(3rd can out of tolerance) * P(4th can out of tolerance) * P(5th can out of tolerance)  

= (0.03 ) * (0.03) * (0.03) * (0.03) * (0.03) =  2.43 E⁻⁸   (2.43 ˣ 10⁻⁸)

Question B:

Probability that exactly two are out of tolerance

= P(1st can is out of tolerance) * P(2nd can is out of tolerance) * P(3rd can is not out of tolerance) * P(4th can is not out of tolerance) * P(5th can is not out of tolerance)

= (0.03) * (0.03) * (0.97) * (0.97) * (0.97) = 0.0008214057

Explanation:

A semicircular loop of radius a in free space carries a current I. Determine the magnetic flux density at the center of the loop.

Answers

Answer: the magnetic flux density at the center of the loop is μ₀I  / 4πα

Explanation:

Taking a look at the diagram;

we draw an imaginary curve to complete it as a circle.

we can now apply amperes law to write;

flux density B at centre;

∫B.dl = μ₀I

now since;

∫dl = 2πα

and field direction at centre is perpendicular to the screen, so it add up , and hence constant in magnitude.

so we can be taken out of the integral ,

B( 2πα ) = μ₀I

hence ;

B_circle = B = μ₀I  / 2πα

so if we remove the half part of this;

we get a semicircle, which is what we are looking for;

Now

B_semi = 1/2.B = 1/2 × μ₀I  / 2πα

B_semi = μ₀I  / 4πα

Therefore the magnetic flux density at the center of the loop is μ₀I  / 4πα

please what is dif
ference between building technology and building engineering.​

Answers

Answer:

Building technology is building technology such as coding an app or a website

Building engineering is making computers or cars or phones

Explanation:

From my perspective:

Building Engineering consists of overall design needs. Working under an architectural firm, to produce a design of structural, mechanical, electrical etc. that will meet various code, cost constraints. Producing construction documents such as plans and specifications.

Building technology consists more of hands on installation and construction management.
Building trade technicians, follow design documents procuring and installing materials and equipment to deliver building systems that meet desired customer end results.

If a more detailed answer is required, probe with search engine. Getting a building from conception to finished product is complicated, typically does not conform to assembly line/repetitive approach.

Compute the solution to x + 2x + 2x = 0 for Xo = 0 mm, vo = 1 mm/s and write down the closed-form expression for the response.

Answers

Answer:

β = [tex]\frac{c}{\sqrt{km} }[/tex] =  0.7071 ≈ 1 ( damping condition )

closed-form expression for the response is attached below

Explanation:

Given :  x + 2x + 2x = 0   for Xo = 0 mm and Vo = 1 mm/s

computing a solution :

M = 1,

c = 2,

k = 2,

Wn = [tex]\sqrt{\frac{k}{m} }[/tex]  = [tex]\sqrt{2}[/tex]  

next we determine the damping condition using the damping formula

β = [tex]\frac{c}{\sqrt{km} }[/tex] =  0.7071 ≈ 1

from the condition above it can be said that the damping condition indicates underdamping

attached below is the closed form expression for the response

please help me make a lesson plan. the topic is Zigzag line. and heres the format.
A. Objective
B. Subject matter
C. Learning activities.
D. Assessment.
E. Reinforcement​

Answers

Explanation:

D. B. C. A. E. Is this a good idea

A magnesium–lead alloy of mass 7.5 kg consists of a solid α phase that has a composition just slightly below the solubility limit at 300°C.
(a) What mass of lead is in the alloy?
(b) If the alloy is heated to 400°C, how much more lead may be dissolved in the αα phase without exceeding the solubility limit of this phase?

Answers

Answer:

(a)This portion of the problem asks that we calculate, for a Pb-Mg alloy, the mass of lead in 7.5 kg of thesolidphase at 300C just below the solubility limit.From Figure 9.20, the solubility limit for thephase at

Explanation:

A rectangular channel 3-m-wide carries 12 m^3/s at a depth of 90cm. Is the flow subcritical or supercritical? For the same flowrate, what depth will five critical flow?

Answers

Answer:

Super critical

1.2 m

Explanation:

Q = Flow rate = [tex]12\ \text{m}^3/\text{s}[/tex]

w = Width = 3 m

d = Depth = 90 cm = 0.9 m

A = Area = wd

v = Velocity

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

[tex]Q=Av\\\Rightarrow v=\dfrac{Q}{wd}\\\Rightarrow v=\dfrac{12}{3\times 0.9}\\\Rightarrow v=4.44\ \text{m/s}[/tex]

Froude number is given by

[tex]Fr=\dfrac{v}{\sqrt{gd}}\\\Rightarrow Fr=\dfrac{4.44}{\sqrt{9.81\times 0.9}}\\\Rightarrow F_r=1.5[/tex]

Since [tex]F_r>1[/tex] the flow is super critical.

Flow is critical when [tex]Fr=1[/tex]

Depth is given by

[tex]d=(\dfrac{Q^2}{gw^2})^{\dfrac{1}{3}}\\\Rightarrow d=(\dfrac{12^2}{9.81\times 3^2})^{\dfrac{1}{3}}\\\Rightarrow d=1.2\ \text{m}[/tex]

The depth of the channel will be 1.2 m for critical flow.

Based on the pattern, what are the next two terms of the sequence? 9,94,916,964,9256,... A. 91024,94096 B. 9260,91028 C. 9260,9264 D. 91024,91028

Answers

Answer:

The answer is "Option A".

Explanation:

Series:

[tex]9, 94, 916, 964, 9256, ........[/tex]

Solving the above series:

[tex]\to 9\\ \to 9(4) =94\\\to 9 (4^2) = 9(16) =916\\\to 9 (4^3) = 9(64) =964\\\to 9 (4^4) = 9(256) =9256\\\to 9 (4^5) = 9(1024) =91024\\\to 9 (4^6) = 9(4096) =94096\\[/tex]

So, the series is:  [tex]9, 94, 916, 964, 9256, 91024, 94096, .................[/tex]

A three-phase motor rated 25 hp, 480 V, operates with a power factor of 0.74 lagging and supplies the rated load. The motor efficiency is 96%. Calculate the motor input power, reactive power and current.

Answers

Answer:

the motor input power is 19.42 KW

the Reactive power is 17.65 KVAR

Current is 31.56 A

Explanation:

Given that;

V = 480V

h.p = 25 hp

p.f = 0.74 lagging

n_motor = 96%

so output = 25hp

and we know that;

1hp = 746 watt

watt = hp × 1hp

so output in watt = 25 × 746 = 18650 Watt = 18.65 KW

n_motor = (output / input) × 100

96 = 1865 / Input

96Input = 1865

Input = 1865 / 96

Input = 19.42 KW

Therefore the motor input power is 19.42 KW

P = √( 3 × V × I × cos∅)

19.42 = √( 3 ×480 × I × 0.74)

I = 31.56 A

Therefore Current is 31.56 A

Q = √( 3 × V × I × sin∅)

we know that

cos∅ = 0.74

so ∅ = cos⁻¹(0.74) = 42.26

so we substitute

Q = √( 3 × 480 × 31.56 × sin(42.26))

 = 17.65 KVAR

Therefore the Reactive power is 17.65 KVAR

A battery with a nominal voltage of 200-V with a resistance of 10 milliohms to be charged at a constant current of 20 amps from a 3-phase semi-converter with a 220-V (line-to-line) Y-connected 60 Hs supply. Determine:

a. The firing angle of the thyristors for the charging process.
b. The displacement power factor and the supply power factor.

Answers

Answer:

a)  ( ∝ ) = 69.6548

b) supply power factor = 0.6709

  displacement power factor = 0.8208

Explanation:

Given data:

Nominal voltage ( E ) = 200-V

resistance (r) = 10 milliohms

constant current ( I )  = 20 amps

Phase ; 3-phase

semi-converter  with 220-v ( line-to-line ) ,  220√2  ( phase voltage )

frequency ; 60 Hz

a) determine the firing angle of thyristors

Vo = E + I*r

    = 200 + 20*10*10^-3

    = 200.2 v

attached below is the remaining part of the solution

firing angle of thyristors for charging process ( ∝ ) = 69.6548

b) determine displacement power factor and supply power factor

attached below is the detailed solution

Displacement power factor ( Dpf ) = cos ( ∝ /2 ) = 0.8208

displacement power factor = g * Dpf

                                             = 0.81747 * 0.8208 = 0.6709

A single phase inductive load draws 10 MW at 0.6 power factor lagging. Draw the power triangle and determine the reactive power of a capacitor to be connected in parallel with the load to raise the power factor to 0.85.

Answers

Answer: attached below is the power triangles

7.13589 MVAR

Explanation:

Power ( P1 ) = 10 MW

power factor ( cos ∅ ) = 0.6 lagging

New power factor = 0.85

Calculate the reactive power of a capacitor to be connected in parallel

Cos ∅ = 0.6

therefore ∅ = 53.13°

S = P1 / cos ∅ = 16.67 MVA

Q1 = S ( sin ∅ ) = 13.33 MVAR  ( reactive power before capacitor was connected in parallel )

note : the connection of a capacitor in parallel will cause a change in power factor and reactive power while the active power will be unchanged i.e. p1 = p2

cos ∅2 = 0.85 ( new power factor )

hence ∅2 =  31.78°

Qsh ( reactive power when power factor is raised to 0.85 )

= P1 ( tan∅1 - tan∅2 )

= 10 ( 1.333 - 0.6197 )

= 7.13589 MVAR

Copy bits 3..0 in $s1 to 6..3 in $s2. Bits 6..3 in $s2 are already set to 0. Registers$s0 0..01111$s1 0..0101$s3 0

Answers

Answer:

Following are the solution to this question:

Explanation:

To copy 3.0 bits in 50 dollars or run at 50 dollars, it takes just 3.0 bits as well as other bits but masks, and 50 dollars.  

Instead of shifting the $ 50 by 3 bits to 6...3 bits of [tex]\$ \ 50, \$ \ 50,0*0000 0003,[/tex] This procedure instead took place at $53 and $50  

AND [tex]\$ \ 50,\$ \ 50,0*0000 000f[/tex], take 3..0  bits

SLL [tex]\$ \ 50, \$ \ 50,0*0000 0003,[/tex]Shifts the bits to 6..3

O R [tex]\$ \ 53,\$ \ 53,\$ \ 50 ,[/tex] coping to [tex]\$ \ 53[/tex]

It is important to keeo a copy of your written plan and safety record s off-site. True or false

Answers

Answer:

The answer for the question is true

Explanation:

If you get a virus or get hacked you will still have it saved

A 13.7g sample of a compound exerts a pressure of 2.01atm in a 0.750L flask at 399K. What is the molar mass of the compound?a. 318 g/mol
b. 204 g/mol
c. 175 g/mol
d. 298 g/mol

Answers

Answer: Option D) 298 g/mol  is the correct answer

Explanation:

Given that;

Mass of sample m = 13.7 g

pressure P = 2.01 atm

Volume V = 0.750 L

Temperature T = 399 K

Now taking a look at the ideal gas equation

PV = nRT

we solve for n

n = PV/RT

now we substitute

n = (2.01 atm x 0.750 L) / (0.0821 L-atm/mol-K x 399 K )

= 1.5075 / 32.7579

= 0.04601 mol

we know that

molar mass of the compound = mass / moles

so

Molar Mass = 13.7 g / 0.04601 mol

= 297.7 g/mol  ≈ 298 g/mol

Therefore Option D) 298 g/mol  is the correct answer

Which of the following is an example of someone who claims that the media has a shooting blanks effect?

A. "Along with parents, peers, and teachers, the media socializes children about how boys and girls are supposed to behave."

B. "My kid saw a cigarette ad in a magazine and now he's smoking. It's the magazine's fault!"

C. "The media doesn't affect me at all because I'm smart enough to know the difference between right and wrong."

D. "There is no definitive evidence that the media affects our behavior"

Answers

Answer:

the answer would be d its d

Answer:

Pretty sure the answer is "C"

Explanation:

"The media doesn't affect me at all because I'm smart enough to know the difference between right and wrong."

Series aiding is a term sometimes used to describe voltage sources of the same polarity in series. If a 5 V and a 9 V source are connected in this manner, what is the total voltage?

Answers

Answer:Total Voltage = 14V

Explanation: it is possible that a circuit  can contain more than one source of electromotive force which can cause flow of current in the same or opposite direction . When the  connection to  voltage sources  allows for current  from the voltage sources to flow in  same direction,it is termed  Series aiding  Thus, the  Total/effective voltage in a series aiding circuit is  computed as the sum of series aiding voltages .

 Here we have the series aiding voltages to be 5V and 9V ,

therefore,

Total Voltage = 5V + 9V

= 14V

A fluid has a mass of 5 kg and occupies a volume of 1 m3 at a pressure of 150 kPa. If the internal energy is 25000 kJ/kg, what is the total enthalpy?

Answers

Answer:

155 KJ

Explanation:

The total enthalpy is given by

ΔH=ΔU + PV

Where;

ΔH = enthalpy

ΔU = internal energy = 25000 kJ/kg/ 5 kg = 5000 KJ

P = 150 kPa = 150,000 Pa

V =  1 m3

ΔH=  5000 + (150,000 * 1)

ΔH=  155 KJ

Air enters an adiabatic turbine at 900 K and 1000 kPa. The air exits at 400 K and 100 kPa with a velocity of 30 m/s. Kinetic and potential energy changes are negligible. If the power delivered by the turbine is 1000 kW.

Required:
a. Find the mass flow rate.
b. Find the diameter of the duct at the exit.

Answers

hooooooooooooooooooooooooooooooooooooooooooooooooooooooe    

Air ows steadily in a thermally insulated pipe with a constant diameter of 6.35 cm, and an average friction factor of 0.005. At the pipe entrance, the air has a Mach number of 0.12, stagnation pressure 280 kPa, and stagnation temperature 825 K. Determine:

a. The length of pipe required to reach the sonic state
b. The static pressure and temperature at the exit if the pipe is 25 m long

Answers

Solution:

Given :

D = 6.35 cm

[tex]$\bar f = 0.005$[/tex]

[tex]$P_s = 280 \ kPa$[/tex]

[tex]$T_s= 825 K[/tex]

a). From fanno flow table (γ = 1.4)

At [tex]$M_1 = 0.12$[/tex] ,    [tex]$\left(\frac{4 \bar f L_{max}}{D}\right)_1 = 45.408$[/tex]

At [tex]$M_2 = 1$[/tex] ,      [tex]$\left(\frac{4 \bar f L_{max}}{D}\right)_2 = 0$[/tex]

∴  [tex]$\left(\frac{4 \bar f L_{max}}{D}\right)_1 - \left(\frac{4 \bar f L_{max}}{D}\right)_2 = \frac{4 \bar f L}{D}$[/tex]

[tex]$45.408 - 0 = \frac{4 \times 0.005 \times L}{0.0635}$[/tex]

[tex]$45.408 = \frac{4 \times 0.005 \times L}{0.0635}$[/tex]

L = 144.17 m

b). If L = 25 m

[tex]$\frac{4 \bar f L}{D}=\frac{4 \times 0.005 \times 25}{0.0635} = 7.874$[/tex]

From fanno flow , (γ = 1.4)

[tex]$At, M_2 = 0.26 , \frac{4 \bar f L}{D} = 7.874$[/tex]

[tex]$\frac{P_s}{P_1}=\frac{T_s}{T_1}^{\frac{\gamma}{\gamma - 1}} = (1+\frac{\gamma-1}{2}M_1^2)^{\frac{\gamma}{\gamma - 1}}$[/tex]

[tex]$\frac{280}{P_1}=\frac{825}{T_1}^{\frac{1.4}{1.4 - 1}} = (1+\frac{1.4-1}{2}(0.12)^2)^{\frac{1.4}{1.4 - 1}}$[/tex]

[tex]$\frac{280}{P_1}=\left(\frac{825}{T_1}\right)^{3.5} =1.0101$[/tex]

[tex]$P_1 = 277.2 \ kPa$[/tex]

[tex]$T_1=822.63 \ K$[/tex]

[tex]$\frac{T_2}{T_1}=\frac{1+\frac{\gamma -1}{2}M_1^2}{1+\frac{\gamma -1}{2}M_2^2}$[/tex]

[tex]$\frac{T_2}{822.63}=\frac{1+\frac{1.4 -1}{2}(0.12)^2}{1+\frac{1.4 -1}{2}(0.26)^2}$[/tex]

[tex]$\frac{T_2}{822.63}=\frac{1.00288}{1.01352}$[/tex]

[tex]$T_2=814 \ K$[/tex]

[tex]$\frac{P_2}{P_1}=\frac{M_1}{M_2}\left(\frac{1+\frac{\gamma -1}{2}M_1^2}{1+\frac{\gamma -1}{2}M_2^2}\right)^{1/2}$[/tex]

[tex]$\frac{P_2}{P_1}=\frac{0.12}{0.26}\left(\frac{1+\frac{1.4 -1}{2}(0.12)^2}{1+\frac{1.4 -1}{2}(0.26)^2}\right)^{1/2}$[/tex]

[tex]$\frac{P_2}{277.2}=0.459$[/tex]

[tex]$P_2=127.27 \ kPa$[/tex]

Explain combined normal and shear stresses with sketch. Write the general expression for (a) Normal and shear stresses on inclined plane (b) principal and maximum shear stresses and identify all the terms in the expression including units.

Answers

Answer:

a) Normal stress :

бn =[ ( бx + бy ) / 2  + ( бx - бy ) / 2  ] cos2∅ + Txysin2∅

shear stress

Tn = ( - бx - бy ) / 2  sin2∅ + Txy cos2∅

b) principal stress :

б1 = ( бx + бy ) / 2  - [tex]\sqrt{}[/tex]( ( бx - бy ) / 2 )^2 + T^2xy

maximum shear stress:

Tmax  = ( б1 - б2) / 2 = √ (( бx - бy ) / 2 )^2 + T^2xy

Explanation:

Combined normal stress and shear stress  sketches attached below

The terms in the sketch are :

бx = tensile stress in x direction

бy =  tensile stress in y direction

Txy = y component of shear stress acting on the perpendicular plane to x axis

бn = Normal stress acting on the inclined plane EF

Tn = shear stress acting on the inclined plane EF

A) Normal and shear stresses on inclined plane

Normal stress :

бn =[ ( бx + бy ) / 2  + ( бx - бy ) / 2  ] cos2∅ + Txysin2∅

shear stress

Tn = ( - бx - бy ) / 2  sin2∅ + Txy cos2∅

B) principal and maximum shear stresses

principal stress :

б1 = ( бx + бy ) / 2  - [tex]\sqrt{}[/tex]( ( бx - бy ) / 2 )^2 + T^2xy

maximum shear stress:

Tmax  = ( б1 - б2) / 2 = √ (( бx - бy ) / 2 )^2 + T^2xy

Other Questions
i love my dads>:))))grr grr grrgrr grrgrr>:(( Which inequality is represented by this graph? How did many celebrities, such as Charlie Chaplin, contribute to the American war effortduring World War I?They helped promote bonds that helped America fund the war, known as Liberty BondsMany European celebrities were secretly pacing information to American intelligence servicesThey appeared in propaganda spots where they mocked the German Kaiser, thus making himless threatening and raising American moraleThey significantly helped Woodrow Wilson in reelection campaign which he ran on the premisethat he would intervene in what was then called The Great War Write an equation in point -slope form with given information slope is -5 point at (-3,8) Why is the system of checks and balances in place?to make sure the Supreme Court can pick presidential candidatesto make sure no part of the government becomes too powerfulto make sure Congress can veto bills proposed by the presidentto make sure the president has absolute authority What is the product of 0.4 and 0.9 Which graph can be used to find the solution of the following system of equations? A figure has vertices at K(5, 5), L(5, 3) , and M(1, 1) . After a rotation 90CCW around point (0, 1) , what are the coordinates of K The temperature increases from 18 F to 27 F.What is the percent increase of the temperature?A3%B9%33%D50% hacer que el pasado sea simple positivo, negativo o pregunta1.I________(not/drink) any beer last night.2.she_______(get on) the bus in the centre of the city 3.what time________(he/get up) yesterday?4.where_______(you/get off) the train?5.I___________(not/change) trains at victoria6.we_____(wake up) very late.porfa es para hoyyyy What did horse man believe about education for all? Two rectangular picture frames have the same area of 45 square inches but have different side lengths. Frame A has a length of 6 3/4 inches, and Frame B has a length of 7 1/2 inches. HELPPPPPPP ASAPPPPPP PLEASEEEE which of the following characteristics is true about an organism whose remains formed a good index fossil.a.) it must be unique orgsnismb.) it must be an organism that lived all around the world c.) it must be an organism that lived for a very short time period d.) all of these characters are important fo an index fossil My Lou Vee Air Car's propeller rotates, but it does not move the car forward. Can someone please help?? This is due on Monday! (5i-3)(9i+1)Answer must be in standard form Read the last paragraph of the story again. Do you think Montresor feels any regret for killing Fortunato in the story? Can somebody plz answer both these questions! They are from the giver Chapters 11-15Only answer in 2-3 sentences if u can :)MARKING BRAINLIEST Hi! Just wondering, do y'all know another language besides English, and if so, what is it? If you only know English, which one would you want to know as a sedond language? Helps me solve this problem please