Guys I need help plz and can you show work also thx

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Step-by-step explanation:

Answer:

120 square inches

Step-by-step explanation:

From the above question, we are told that:

Rectangle ABCD is similar to Rectangle WXYZ .

The area of ABCD is 30 square inches.

We are also given the ratio of their side length = 1/2

To the find the area of the second rectangle, the scale factor = k² is required where:

k = ratio of the side lengths

Let us represent the area of the.secind Rectangle as = x

Because the ratio of the corresponding side lengths is 1/2, the ratio of the areas is equal to (1/2 ) to the second power.

Hence

30/x = k²

30/x = (1/2)²

30/x = 1/4

We cross Multiply

= 30 × 4 = x

x = 120 square inches.

Therefore, the area of Rectangle WXYZ is 120 square inches.

Answer:

Option (4)

Step-by-step explanation:

Parent function of the graph attached,

f(x) = [tex]\sqrt{x}[/tex]

If the given function is shifted by 'a' units to the left,

Rule for the transformation is,

g(x) = f(x + a)

So the transformed function will be in the form of g(x) = [tex]\sqrt{x+a}[/tex]

Therefore, from the given options, f(x) = [tex]\sqrt{x+4}[/tex] will match our requirements.

Option (4) will be the answer.

Answer:

D

Step-by-step explanation:

Answer:

200,000

80,000

9,000,000

10,000,000,000

What is the context of this question?

Step-by-step explanation:

Answer:

So standard form just means 200,000 written as like 200^ something(I think)

Step-by-step explanation:

Answer:

Using PEDMAS, you would have to do the parentheses part first(you would multiply 5 by 4 and 5 by -1.5x.

Step-by-step explanation:

Answer:

Step-by-step explanation:gdndvdsjfehsk

Answer:

Step-by-step explanation:

The three best questions to ask would be the following

Most bank checkings account charges fees and these fees may or may not be hidden. These can include maintenance fees, overdraft fees, balance fees, etc. and can stack up if not managed correctly. Therefore it is best to know beforehand.

One of the main things that set these accounts apart between banks are the bonuses and rewards. Some banks may offer a sign-up bonus which can be 200$ or higher when opening a new account. Others may offer higher interest rates for returning customers, or even a physical reward for spending money or depositing a certain amount into the account. These are features that set the different banks apart.

Lastly, would be the interest rate. This is especially important if you have a large sum of money that will be in the account as your money can generate more money with an interest rate. Banks may offer anywhere between 1% to 3% annual interest rate. This can be a deciding factor when choosing one bank over another.

Answer:

the picture is blurry is it only like that for me?

Answer:

y=1/2x-1

Step-by-step explanation:

0,-1

2,0

0--1 si 1

2-0 is 2

1/2

Answer:

It would be 18/40 and his grade would be a 45%

Answer:

24

Step-by-step explanation:

18/30×40=24

Angle A = 3x - 10

Angle B = x

Their angle sum = 90° ( complementary angles form 90° )

This can be written in an equation as =

= 3x - 10 + x = 90

= 3x + × + ( -10 ) = 90

= 4x + (-10) = 90

= 4x = 90 + 10 ( transposing-10 from LHS to RHS changes-10 to +10 )

= 4x = 100

= x = 100 ÷ 4 ( transposing ×4 from LHS to RHS changes ×4 to ÷4 )

= x = 25

Angle A = 3x - 10

= 3 × 25 - 10

= 75 - 10

= Angle A = 65°

Angle B = x = 25°

Their sum = 65 + 25 = 90°

Therefore , the complementary angles , Angle A = 65° and Angle B = 25° .

Answer:

3.8146973e+12

Step-by-step explanation:

you have to do 5x5 18 times to get this answer.

Answer:

The two on the top

Answer:

(x2 +16)⋅(x+3)

Step-by-step explanation:

Answer: 37

Step-by-step explanation:

Use A squared plus b squared equals c squared.

1. 35 squared is 1,225.

2. 12 squared is 144.

3. 144 plus 1,225 is 1,369. Now is 1,369 a square number?

Well the square root of 1,369, that's 37.

Answer:

Step-by-step explanation:

League A                   League B

151.12                            163.25

148                                157

26.83                             24.93

29                                  136

136                                145

167                                178

207                               256

League A in ascending order :

26.83 , 29 , 136, 148 , 151.12 , 167,207

[tex]Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{26.83+29 +136+ 148+ 151.12+ 167+207}{7}\\\\Mean =123.564[/tex]

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=148

Standard deviation=[tex]\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}[/tex]=[tex]=\sqrt{\frac{(26.83-123.564)^2+(29-123.564)^2+.......+(207-123.564)^2}{7}}=63.98[/tex]

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 26.83 , 29 , 136, 148

n = 4

Q1=82.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 148 , 151.12 , 167,207

n = 4

Q3=159.06

IQR = Q3-Q1=159.06-82.5=76.56

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

[tex](82.5-1.5\times 76.56,159.06+1.5\times 76.56)[/tex]

(-32.34,273.9)

So, There is no outlier

Maximum = 207

2)

League B in ascending order :

24.93,136,145,157,163.25,178,256

[tex]Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{24.93+136+145+157+163.25+178+256}{7}\\\\Mean =151.45[/tex]

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=157

Standard deviation=[tex]\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}[/tex]=[tex]=\sqrt{\frac{(24.93-151.45)^2+(136-151.45)^2+.......+(256-151.45)^2}{7}}=68.42[/tex]

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 24.93,136,145,157

n = 4

[tex]Median = \frac{\frac{n}{2} \text{th term}+(\frac{n}{2}+1) \text{th term}}{2}\\Median = \frac{\frac{4}{2} \text{th term}+(\frac{4}{2}+1) \text{th term}}{2}\\Median = \frac{2 \text{th term}+3 \text{th term}}{2}\\Median = \frac{136+145}{2}=140.5[/tex]

Q1=140.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 157,163.25,178,256

n = 4

Q3=170.625

IQR = Q3-Q1=170.625-140.5=30.125

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

[tex](140.5-1.5\times 30.125,170.625+1.5\times 30.125)[/tex]

(95.3125,215.8125)

24.93 and 256 are outliers  

Maximum = 256

Answer:

Position = -5

Step-by-step explanation:

The number line is not shown, however the question can still be answered.

Given

Start Point: +2

Left Movement: 3.5cm and 7.9cm

Right Movement: 4.8cm

Required

Determine the Ant's position

To do this, we treat all left movements as negative and all right movements as positive.

So, we have:

Position = 2 - 3.5 - 7.9 + 4.8

Position = -4.6

Since the number line is spaced by 1cm, we have to approximate to the nearest integer.

Position = -5

Answer:

10 and 11

Step-by-step explanation:

10 and 11.

These are the closest whole numbers, because the square root of 100 is 10, and the square root of 121 is 11.

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Answer:

a. intersecting

b. parallel

c. skew

d. intersecting

e. parallel

Answer:

∠ Q = 75°

Step-by-step explanation:

Since PR and PQ are equal then the triangle is isosceles, thus

the base angles R andQ are congruent

The sum of the 3 angles in a triangle = 180°

Sum the 3 angles and equate to 180

x + 2x + 15 + 2x + 15 = 180, that is

5x + 30 = 180 ( subtract 30 from both sides )

5x = 150 ( divide both sides by 5 )

x = 30

Thus

∠ Q = 2x + 15 = 2(30) + 15 = 60 + 15 = 75°

Answer:

x=3

x=−3

Step-by-step explanation:

Answer:

Step-by-step explanation:

BD divides CBA into two angles. The add to 90 degrees. Therefore they are complementary.

The key word is complementary. The angles are <CBA and <DBA are complementary.

Answer:

Right angle or adjacent angle. I'm not sure if there was a vocabulary bank.

Step-by-step explanation:

Answer:

−987889880538

Step-by-step explanation:

Answer:

-987889880538

Step-by-step explanation:

ez

Answer:

[tex]x = 3[/tex]

Step-by-step explanation:

Simply divide both sides of the equation by 6 and it'll be the answer.

Answer:

4y=16 is true if you do the problem you can see it wont work and i simplified and got the answer

Step-by-step explanation:

The answer is to the question is c.11