Answer:
22 m/s
Explanation:
PEf +KEf =PE0 +KE0 →PE0 −PEf =KEf
−mgΔy= 1 mv2 →v= −2gΔy = −2(9.8 m/s2)(−25 m)=22 m/s
Two objects attract each other with a gravitational force of magnitude 1.01 10-8 N when separated by 19.9 cm. If the total mass of the two objects is 5.11 kg, what is the mass of each?
Answer:
m₂ = 1.17 kg
Explanation:
Given that,
Force between two objects, [tex]F=1.01\times 10^{-8}\ N[/tex]
Mass of object 1, [tex]m_1=5.11\ kg[/tex]
Distance between masses, r = 19.9 cm = 0.199 m
The gravitational force between two masses is given by :
[tex]F=\dfrac{Gm_1m_2}{r^2}[/tex]
m₂ is the mass of object 2
[tex]m_2=\dfrac{Fr^2}{Gm_1}\\\\m_2=\dfrac{1.01\times 10^{-8}\times (0.199)^2}{6.67\times 10^{-11}\times 5.11}\\\\=1.17\ kg[/tex]
So, the mass of second object is 1.17 kg.
5.
An 80 newton force and a 45 newton force act on an object
as shown below.
80 N
30°
4S N
Which of the following vectors would bets represent an
equilibrant when added to this system?
(1) 24 N to the left (3) 24 N to the right
(2) 114 N to the right (4) 45 N to the left
Tirant Showroiculations
Answer:
the answer is a time your welcome
Answer:
(1)
Explanation:
A jogger runs north 6 km, 5 km east, and 4 km north again. Time is 1.9 hr. What is average velocity?
Answer:
Average velocity = 5.9 km/ hr (or 1.64 m/s).
Explanation:
Velocity = [tex]\frac{displacement}{time}[/tex]
It is a vector quantity and has an SI unit of m/s.
Displacement = [tex]\sqrt{x^{2} + y^{2} }[/tex]
x = 5 km east
y = 6 km north + 4 km north
= 10 km north
So that,
Displacement = [tex]\sqrt{5^{2} + 10^{2} }[/tex]
= [tex]\sqrt{25 + 100}[/tex]
= [tex]\sqrt{125}[/tex]
= 11.1803
Displacement = 11.18 km = 11180 m
Time = 1.9 hr = 6840 seconds
Average velocity = [tex]\frac{11.180}{1.9}[/tex]
= 5.8842
Average velocity = 5.9 km/ hr
The average velocity is 5.9 km/ hr (or 1.64 m/s).
A relaxed spring of length 0.15 m stands vertically on the floor; its stiffness is 1070 N/m. You release a block of mass 0.5 kg from rest, with the bottom of the block 0.6 m above the floor and straight above the spring. How long is the spring when the block comes momentarily to rest on the compressed spring?
Answer:
x' = 0.085 m = 8.5 cm
Explanation:
The law of conservation of energy says that:
Potential Energy Stored in Spring = Loss in Gravitational Potential Energy of Block
(1/2)kΔx² = mgh
where,
k = stiffness of spring = 1070 N/m
Δx = change in length of spring = ?
m = mass of block = 0.5 kg
g = 9.8 m/s²
h = height of block above spring = 0.6 m - 0.15 m = 0.45 m
Therefore,
(1/2)(1070 N/m)Δx² = (0.5 kg)(9.8 m/s²)(0.45 m)
Δx = √[2(2.205 Nm)/(1070 N/m)]
Δx = 0.064 m
but,
Δx = x - x' = 0.15 m - x' = 0.064 m
x' = 0.15 m - 0.064 m
x' = 0.085 m = 8.5 cm
What does the underlined word mean in the following sentence? El conejo viene el día de Pascua de Resurrección. Easter Christmas Holidays Thanksgiving
Answer:easter
Explanation:
Answer:
Easter
Explanation:
did it on edge, and searched it up
A college student has just bought a small computer that weighs 50N. Her apartment is on the 5th floor which is 35 meters up. How much work must she do to drag her computer up the stairs?
Answer:
W = 1750 J
Explanation:
It is given that,
Weight of a computer, F = 50 N
A student wants to keep it on the 5th floor which is 35 meters up.
We need to find the work done by her to drag her computer up the stairs. Let it is W. Using the formula of work as follows :
W = F d
Put all the values,
W = 50 N × 35 m
W = 1750 J
So, 1750 J of work is done by her to drag the computer up the stairs.
If a 4N weight is hung on a spring, and it extends by 0.2m, what is the spring constant (k)?
Answer: 200 N/m
Explanation:
The Gravitational spring energy(Us) is equal to 1/2kx^2. So we have x as .2 m and Us as 4 N. So 4 N = 1/2 * k * .2^2. So now we solve for K and get 200 N/m.
Answer:
20 N/m
Explanation:
4/0.2 = 20 N/m
/ = divide
A 50 g mass is freely hanging from a horizontal meter stick at a distance of 99 cm from the pivot. Calculate the weight force W that the mass exerts on the meter stick? ·Calculate the torque that the weight force exerts about the pivot? 4. What does the pivot exert on the meter stick?
Answer:
W = 0.49 N
τ = 0.4851 Nm
Force
Explanation:
The weight force can be found as:
W = mg
W = (0.05 kg)(9.8 m/s²)
W = 0.49 N
The torque about the pivot can be found as:
τ = W*d
where,
τ = torque
d = distance between weight and pivot = 99 cm = 0.99 m
Therefore,
τ = (0.49 N)(0.99 m)
τ = 0.4851 Nm
The pivot exerts a FORCE on the meter stick because the pivot applies force normally over the stick and has a zero distance from stick.
A 0.200 H inductor is connected in series with a 88.0 Ω resistor and an ac source. The voltage across the inductor is vL=−(12.0V)sin[(487rad/s)t].
Required:
a. Derive an expression for the voltage vR across the resistor. Express your answer in terms of the variables L, R, VL (amplitude of the voltage across the inductor), ω, and t .
b. What is vR at 2.00 ms? Express your answer with the appropriate units.
Answer:
a. (VL)R/ωL[1 - cos[ωt]] = (10.84 V)[1 - cos[(487rad/s)t]]
b. 1.084 mV
Explanation:
a. Since it is a series circuit, the current in the inductor is the same as the current in the resistor.
Now, the voltage across the inductor vL = -Ldi/dt.
So, the current, i = -1/L∫vLdt.
Now, vL = −(12.0V)sin[(487rad/s)t] and L = 0.200 H
Substituting these into i, we have
i = -1/L∫vLdt
= -1/0.200H∫[−(12.0V)sin[(487rad/s)t]]dt.
= -[−(12.0V)]/0.200H∫[sin[(487rad/s)t]]dt.
= 60V/H∫[sin[(487rad/s)t]]dt
Integrating i, we have
i = 60V/H ÷ [(487rad/s)[-cos[(487rad/s)t]] + C
at t = 0, i(0) = 0
0 = 60V/H ÷ [(487rad/s)[-cos[(487rad/s)× 0]] + C
0 = 60V/H ÷ [(487rad/s)[-cos[0]] + C
0 = 60V/H ÷ [(487rad/s)[-1]+ C
C = 60V/H ÷ [(487rad/s)
So, i = 60V/H ÷ [(487rad/s)[-cos[(487rad/s)t]] + 60V/H ÷ [(487rad/s)
i = 60V/H ÷ [(487rad/s)[1 - cos[(487rad/s)t]]
i = (0.123A)[1 - cos[(487rad/s)t]] = VL/ωL[1 - cos[ωt]] where ω = 487rad/s and VL = 12.0 V and L = 0.200 H
So, the voltage across the resistor vR = iR where R = resistance of resistor = 88.0 Ω
So, vR = iR = VL/ωL[1 - cos[ωt]] × R = (VL)R/ωL[1 - cos[ωt]]
= (0.123A)[1 - cos[(487rad/s)t]] × 88.0 Ω
= (10.84 V)[1 - cos[(487rad/s)t]]
b. vR at t = 2.00 ms = 0.002 s
So, vR = (10.84 V)[1 - cos[(487rad/s)(0.002)]]
= (10.84 V)[1 - cos[0.974]]
= (10.84 V)[1 - 0.9999]
= (10.84 V)(0.0001)
= 0.001084
= 1.084 mV
A car covers a distance of 200m. If its velocity is 20 m/s, calculate the time taken.
Answer:
10 seconds
Explanation:
velocity=displacement/timeLisa throws a stone horizontally from the roof edge of a 50 meter high dormitory. It hits the ground at a point 60 m from the building. Find the time of flight.
Answer:
Explanation:
Time of flight is the time of takes to hit the ground
Given
Height H = 50m
Acceleration due to gravity g = 9.8m/s³
Using the equation of motion;
S = ut+1/2gt²
u = 0m/s
Substitute and get time t
50 = 0(t)+1/2(9.8)t²
50 = 4.9t²
t² = 50/4.9
t² = 10.204
t = √10.204
t = 3.19secs
Hence the time of flight is 3.19secs
3. If the bus stop is 0.68 km down the street from the museum and it takes
you 9.5 min to walk north from the bus stop to the museum entrance,
what is your average velocity?
Answer:
0.07km/minExplanation:
Step one:
given data
distance between museum and bus top= 0.68km
time taken to walk from the bus stop to the museum = 9.5min
Required
The average velocity is defined as the rate at which you are moving
The expression for the average velocity is
Average velocity = distance/time taken
Average velocity= 0.68km/9.5
Average velocity= 0.07km/min
Hence your average velocity is 0.07km/min
I want to know about the inventions caused due to rain. Like the Benjamin Franklin's Lightning Conductor. I have to make a chart.
Why are weathering, erosion and deposition a NECESSARY process in the rock cycle?
ANSWER THIS NOW PLEASE! AND YOU GET 225 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
YESS well it is partly nessary but it depends on the situation
Explanation:
Answer:
Weathering, erosion, and deposistion are necessary processes in the rock cycle because:
Explanation:
First, start with igneous rocks. magma erupts (Extrusive igneous rocks) or solidifies in the sub-surface of the earth (Intrusive igneous rock). when they are exposed Weathering and erosion occur which is a slow breakdown of rock through the wind, water, or other processes. The weathered pieces (sediments) move to other places by wind or water and get deposited someplace else. When there are enough sediments and there is overburden pressure on these sediments, they become a sedimentary rock. Due to overburden pressure, they become metamorphic rocks. now the thing to understand here is that when metamorphic rocks are exposed, they too undergo weathering and erosion and their pieces also become sedimentary rocks.
Is Solar Energy renewable? Why or why not? Use in your own words.
Answer:
Solar energy is renewable.
Explanation:
If something is renewable, it is generated faster than it can be reasonably used or won't run out for longer than it would be used. Solar falls into the latter category. Using solar panels won't deplete the sun and the sun will likely be around for much longer than we will.
a current of 200mA through a conductor converts 40 joules of electrical energy into heat in 30 seconds determine the potential drop across the conductor
Answer:
V = 6.65 [volt]
Explanation:
We must first find the power generated, power is defined as the amount of energy consumed or generated in a given time.
[tex]P=\frac{E}{t}[/tex]
where:
P = power [w]
E = energy = 40 [J]
t = time = 30 [s]
[tex]P =40/30\\P = 1.33[w][/tex]
Now we can calculate the voltage or potential drop by means of the power, the power is calculated by means of the product of the voltage by the current.
[tex]P =V*I[/tex]
where:
V = voltage [volts]
I = current = 200mA = 0.2 [A]
[tex]V = P/I\\V = 1.33/0.2\\V = 6.65 [Volt][/tex]
If a dog has a mass of 2.5 kg, what is its weight and what is the normal force that it feels.
I
Answer:
Weight = normal force = 24.5 N
Explanation:
Given that,
Mass of a dog, m = 2.5 kg
We need to find its weight and the normal force that it feels.
The weight of an object is given by :
W = mg
Where g is the acceleration due to gravity
[tex]W=2.5\times 9.8\\\\=24.5\ N[/tex]
The normal force is balanced by the weight of an object. So,
Weight = normal force = 24.5 N
Do you think there is a temperature at which sound cannot be heard?
Answer:
The definition would be defined in the clarification section downwards and according to the given question.
Explanation:
This would be considered a lapse of temperature. The rate of acceleration sometimes gradually decreases, because as the temperature is lowered through height. The latter suggests that perhaps the layer of water nearest to either the surface moves the quickest, as well as the layer of water and the furthest just above the surface, travels the fastest pace, with shock energy passing underground.The waves move and curve vertically as a consequence. This will create an area of the "shadow zone" where the sound couldn’t reach into. Although it could be possible to have seen the origin, a guy standing throughout the loss impairment may not remember the sound. The charged particles are refracted vertically and it's never going to reach the listener.During the stretching routine who used the medicine ball for support.
The guy
The guy
The Girl
The Girl
Both people used a ball for support
Both people used a ball for support
No one used it
No one used it
A car’s brakes decelerate it at a rate of -2.40 m/s2. If the car is originally travelling at 13 m/s and comes to a stop, then how far, in meters, will the car travel during that time?
Answer:
Approximately [tex]35.2\; \rm m[/tex].
Explanation:
Given:
Initial velocity: [tex]u = 13\; \rm m \cdot s^{-1}[/tex].
Acceleration: [tex]a = -2.40\; \rm m \cdot s^{-2}[/tex] (negative because the car is slowing down.)
Implied:
Final velocity: [tex]v = 0\; \rm m \cdot s^{-1}[/tex] (because the car would come to a stop.)
Required:
Displacement, [tex]x[/tex].
Not required:
Time taken, [tex]t[/tex].
Because the time taken for this car to come to a full stop is not required, apply the SUVAT equation that does not involve time:
[tex]\begin{aligned} x &= \frac{v^2 - u^2}{2\, a} \\ &= \frac{{\left(0\; \rm m \cdot s^{-1}\right)}^2 - {\left(13\; \rm m \cdot s^{-1}\right)}^2}{2\times \left(-2.40\; \rm m\cdot s^{-2}\right)} \approx 35.2\; \rm m \end{aligned}[/tex].
In other words, this car would travel approximately [tex]35.2\; \rm m[/tex] before coming to a stop.
How does increasing the width of a wire affect a circuit?
A. It restricts the flow of electrons.
B. It reduces the voltage
C. It allows electrons to flow more easily
D. It increases the resistance
Whoever gets this right I’ll give brainliest. Be sure that the answer is right. I’d love a explanation too if you could include one.
Answer:
The resistance of a wire decreases with increasing thickness.
Explanation:
Hope this helped!
Answer: C it allows electrons to flow more easily
Explanation:i got it right i hope this helps you
Suppose you have a 2000 Watt water heater that is on for a total of 150 hours a month. How much will this cost you at a rate of 10 cents per kW*hr?
Answer:
$30
Explanation:
Given that,
Power of a water heater, P = 2000 Watts
It is on for a total of 150 hours a month.
2000 Watts = 2 kW
Time, t = 150 hours
Energy used by the water heater is given by :
[tex]E=P\times t\\\\E=2\ kW\times 150\ h\\\\E=300\ kWh[/tex]
It is also mentioned that the cost is 10 cents per kWhr.
Since, $1 = 100 cents
10 cents = $0.1
So, the total cost for the month is :
Cost = 300 × 0.1
Cost = $30
So, the required cost is $30.
student measures the weight of a bag of bananas with a spring balance.
Describe what is inside a spring balance and explain how it works.
A spring balance measures the weight of an object by opposing the force of gravity acting with force of an extending spring. May be used to determine mass as well as weight by recalibrating the scale. Some spring balances are available in gram or kilogram markings and are used to measure the mass of an object. Spring balances consist of a cylindrical tube with a spring inside. One end (at the top) is fixed to an adjuster which can be used to calibrate the device. The other end is attached to a hook on which you can hang masses etc.
An ant is crawling along a yardstick that is pointed with the O-inch mark to the east and the 36-Inch mark to the west. It starts at the 19-inch mark, crawls to the 27-inch
mark, then moves to the 7-inch mark. What was the total distance the ant traveled?
Answer:
33 Inches
Explanation:
The movement of the ant is sketched in the attached image. The ant moved from the 19-inch mark to 27-inch mark covering a distance of 13 Inches (27 - 19). Finally, it moved from the 27-inch mark to 7-inch mark covering a distance of 20 Inches (27 - 7).
Total Distance covered = 13 + 20 = 33 Inches.
Hence, the total distance the ant traveled is 33 Inches.
What is Hydroelectric energy used for? Use in your own words.
1. How far away must you be from a 675 kHz radio station with power 50.0 kW for there to be only one photon per second per square meter? Assume no reflections or absorption, as if you were in deep outer space. 2. Discuss the implications for detecting intelligent life in other solar systems by detecting their radio broadcasts.
a) 0.321 ly
b) 0.321 light years is not far in astronomical terms. Alien life would need to transmit at tremendous power in order for their radio transmissions to be detectable. Their radio signal also needs to be stronger than background noise in order to be distinguishable. Therefore it is unlikely that radio transmissions from alien life will ever be detected.
In the pictire ,can we separate hydrogen (H) from oxygen (O)?
Paanswer nga po.....
A.)
Water is the name of the pure substance H₂O
B.)
Hydrogen and Oxygen are the compound of water
C.)
Yes, we can
D.)
This process known as Electrolysis
A small block of mass m1 = 0.4 kg is placed on a long slab of mass m2 = 2.8 kg. Initially, the slab is stationary and the block moves at a speed of vo = 3 m/s. The coefficient of kinetic friction between the block and the slab is 0.15 and there is no friction between the slab and the surface on which it moves.
Determine the speed v1.
Determine the distance traveled by the slab before it reaches the speed v1.
Answer:
v₁ = 0.375 m / s , x = 0.335 m
Explanation:
Let's analyze this interesting exercise, the block moves and has a friction force with the tile, we assume that the speed of the block is constant, so the friction force opposes the block movement. For the only force that acts (action and reaction) this friction force exerted by the block that is in the direction of movement of the tile.
We can also see that the isolated system formed by the block and the tile will reach a stable speed where friction cannot give the system more energy, this speed can be found by treating the system with the conservation of linear momentum.
initial moment. Right at the start of the movement
p₀ = m v₀ + 0
final moment. Just when it comes to equilibrium
[tex]p_{f}[/tex] = (m + M) v₁
how the forces are internal
p₀ =p_{f}
m v₀ = (m + M) v₁
v₁ = m /m+M v₀
let's calculate
v₁ = 0.4 /(0.4 + 2.8) 3
v₁ = 0.375 m / s
Let's apply Newton's second law to the Block, to find the friction force
Y axis
N - W = 0
N = W
N = m g
where m is the mass of the block
the friction force has the formula
fr = μ N
fr = μ m g
We apply Newton's second law to slab
X axis
fr = M a
where M is the mass of the slab
μ m g = M a
a = μ g m / M
let's calculate
a = 0.15 9.8 0.4 / 2.8
a = 0.21 m / s²
With kinematics we can find the position
v²= v₀²+2 a x
as the slab is initially at rest, its initial velocity is zero
v² = 2 a x
x = v2 / 2a
let's calculate
x = 0.375²/2 0.21
x = 0.335 m
How much is the velocity of a body when it travels 600m in 5 minutes?
There are 60 minutes in an hour. Whatever distance a person crosses in 5 mins, he/she can cross 12 times that distance in 1 hour. So, in one hour the person could have crossed 12 X 600 = 7200 meters.
But, 1000 meters equal one kilometer. So, 7200m = 7.2 km. Thus, this person travels 7.2 km in one hour, and hence has a speed of 7.2 km/hr
Answer:
2m/s
Explanation:
V=S/t
v=distance ÷ time
v=600m. × 5mins
v=600/5 ×60
600/300
2m/s
a 1000kg car uses a breaking force of 10,000N to stop in two second. What is the change in momentum of the car?
Answer:
ΔP = 20000 N s
Explanation:
To solve this problem we use the relation between momentum and moment
I = Δp
let's calculate the momentum
I = ∫F dt
if we use the average force
I = F t
I = 10000 2
I = 20000 N s
therefore with the first equation
ΔP = I = 20000 N s