A force of 70 N is inclined at an angle
of 30° to the horizontal. Calculate its
horizontal and vertical components
respectively.
Answer:
The horizontal component of the 70 N force = 35·√3 N
The vertical component of the 70 N force = 35 N
Explanation:
The magnitude of the given force, F = 70 N
The angle of inclination of the given force to the horizontal, θ = 30°
By the resolution of forces, we can resolve the given force, F, into its horizontal component, Fₓ, and vertical components, [tex]F_y[/tex], as follows;
The horizontal component of the given force = Fₓ = F × cos(θ)
Substituting the values, we have;
The horizontal component of the 70 N force, Fₓ = 70 × cos(30°) = 35·√3 N
The vertical component of the given force = [tex]F_y[/tex] = F × sin(θ)
Substituting the values, we have;
The vertical component of the 70 N force, [tex]F_y[/tex] = 70 × sin(30°) = 35 N.
Inserting the formulas you found for Xman(t) and Xbus(t) into the conditionXman(tcatch)=Xbus(tcatch) , you obtain the following-b+ct(catch) = 1/2 at^2( catch) or 1/2 at^2 (catch) - ct (catch) +b = 0Intuitively, the man will not catch the bus unless he is running fast enough. In mathematical terms, there is a constraint on the man's speed (c) so that the equation above gives a solution for t catch that is a real positive number.Find Cmin the minimum value of c for which the man will catch the busExpress the minimum value for the man's speed in terms of a and b .
Answer:
c > √(2ab)
Explanation:
In this exercise we are asked to find the condition for c in such a way that the results have been real
The given equation is
½ a t² - c t + b = 0
we can see that this is a quadratic equation whose solution is
t = [c ±√(c² - 4 (½ a) b)] / 2
for the results to be real, the square root must be real, so the radicand must be greater than zero
c² -2a b > 0
c > √(2ab)
2. A 75 kg runner accelerates from 0.00 m/s to 10.0 m/s in 1.5 seconds.
a) What is the runner's acceleration?
b) How much Kinetic Energy does the runner have at 0.0m/s, 5.0m/s, 10.0 m/s?
c) graph his kinetic energy. Use velocity on the x-axis and KE on the y-axis
Given, Unknown: Equation, Substitute: Solution:
UWU plz help 50 points!!
A sprinter accelerates from the starting blocks with an acceleration of 2.5 m/s/s. They accelerate for a total of 8 seconds.
a. How far will they run while accelerating? Explain how you found your answer.
b. How fast are they moving after those 8 seconds? Explain how you found your answer
Answer:
i think its 20m for b
Explanation:
How is thermal energy transferred during conduction? Check all that apply.
Thermal energy is transferred between particles that are not touching each other.
Thermal energy is transferred between particles that are in direct contact with each other.
Thermal energy is transferred between objects of different temperatures.
Thermal energy is transferred between objects of the same temperature.
Thermal energy is transferred from slow-moving particles to fast-moving particles.
Thermal energy is transferred from fast-moving particles to slow-moving particles.
Answer:
Thermal energy is transferred between particles that are in direct contact with each other.Thermal energy is transferred between objects of different temperatures.Thermal energy is transferred from fast-moving particles to slow-moving particles.Explanation: Correct on Edg 2020/2021 for my school.
Albert Bandura’s theory, originally called social learning theory, is now referred to as __________, and it suggests cognitive processes play a role in influencing one’s personality.
Answer:
social cognitive theory
Explanation:
Albert Bandura's theory, originally called social learning theory, is now referred to as social cognitive theory, and it suggests cognitive processes play a role in influencing one's personality.
Albert Bandura's theory, originally called social learning theory, is now referred to as social cognitive theory, and it suggests cognitive processes play a role in influencing one's personality.
What are cognitive processes?Cognitive processes refer to the mental processes involved in perception, attention, memory, reasoning, problem-solving, and decision-making. They involve the use of knowledge, experience, and understanding to process information and make sense of the world around us.
Here, examples of cognitive processes include perception, attention, memory, language processing, and executive functions such as planning and decision-making. Cognitive processes are essential for learning, problem-solving, and adaptive behavior, and they are an important focus of study in psychology and cognitive science.
Albert Bandura's theory, originally called social learning theory, is now referred to as social cognitive theory, and it suggests cognitive processes play a role in influencing one's personality.
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why the gaps left between succesive rails on a railway tracks
Small gaps which function as expansion joints are deliberately left between the rail ends to allow for expansion of the rails in hot weather. ... Because of these small gaps, when trains pass over jointed tracks they make a "clickety-clack" sound.
The sum of two component vectors is referred to as the
vector.
Addition
Quantitative
Subtraction
Resultant
Find the tension in the two ropes that are holding the 2.9 kg object in place. Rope 1 makes an angle of 51.3° with respect to the vertical. Rope 2 is pulling horizontally.
Answer:
Explanation:
Let the tension in horizontal rope be T₁ and in the other rope be T₂ which is making angle of 51.3⁰
The vertical component of tension T₂ will balance the weight .
= T₂ cos 51.3 = 2.9 x 9.8
T₂ = 2.9 x 9.8 / cos 51.3
= 28.42 / .625
= 45.47 N
The horizontal component of T₂ will balance T₁
T₂ sin 51.3 = T₁
45.47 sin 51.3 = T₁
T₁ = 35.48 N .
a sheet of metal is 2mm wide 10cm tall and 15cm long. it was 4g. what is the density?
Answer:
Ro = 133 [kg/m³]
Explanation:
In order to solve this problem, we must apply the definition of density, which is defined as the relationship between mass and volume.
[tex]Ro = m/V[/tex]
where:
m = mass [kg]
V = volume [m³]
We will convert the units of length to meters and the mass to kilograms.
L = 15 [cm] = 0.15 [m]
t = 2 [mm] = 0.002 [m]
w = 10 [cm] = 0.1 [m]
Now we can find the volume.
[tex]V = 0.15*0.002*0.1\\V = 0.00003 [m^{3} ][/tex]
And the mass m = 4 [gramm] = 0.004 [kg]
[tex]Ro = 0.004/0.00003\\Ro = 133 [kg/m^{3}][/tex]
5. A helicopter scoops a load of water out of a lake, to dump on a forest fire. The helicopter exerts 6480
N of force on the water while rising high enough to fly over a mountain. If the helicopter does 1.62 x
10%) of work on the water while lifting it, how high does it lift the water.
Answer:
h = 250 m
Explanation:
Given that,
The helicopter exerts 6480 N of force on the water while rising high enough to fly over a mountain.
The helicopter does [tex]1.62\times 10^6\ J[/tex] of work on the water lifting it.
We need to find how high does it lift the water. Work done is given by :
[tex]W=Fh\\\\h=\dfrac{W}{F}\\\\h=\dfrac{1.62\times 10^6}{6480}\\\\h=250\ m[/tex]
So, it can lift the water to a height of 250 m.
Which procedure would best demonstrate that moving magnet causes an electric current to flow in a wire coil?
Answer:
D
Explanation:
I took the test
The procedure that would best demonstrate that moving magnet causes an electric current to flow in a wire coil is connect a wire coil to an ammeter. Move a bar magnet into and out of the wire coil as you observe the ammeter. The correct option is D.
What is electric current?The flow of electricity in an electronic circuit, as well as the amount of electricity flowing through a circuit, are referred to as electric current. It is expressed in amperes (A).
The greater the value in amperes, the more electricity flows through the circuit.
When an electron is introduced into a wire, a free electron is attracted to a proton in order to be neutral.
Forcing electrons out of their orbits can result in an electron shortage. Electric current is the continuous movement of electrons in a wire.
Connecting a wire coil to an ammeter is the best way to demonstrate that a moving magnet causes an electric current to flow in a wire coil. As you watch the ammeter, move a bar magnet in and out of the wire coil.
Thus, the correct option is D.
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plz plz plz I beg u solve these questions I will mark u the brainliest
all questions
the first one is c
second is b
third is c
forth is b
Answer:
1. i think its therml...it could be sound too
2. 16m
3.45
4.5.0
A horizontal 52 Newton force is needed to slide a 50-kg box across a flat surface of a constant velocity of 3.5 m s what is the coefficient of kinetic friction between the box and the floor
Answer:
μk = 0.106
Explanation:
When the box is moving across the flat surface with a constant velocity, the force applied on it must be equal to the kinetic frictional force applied on the object:
F = μk*W = μk*mg
Where,
F = Force applied on box = 52 N
m = mass of box = 50 kg
g = 9.8 m/s²
μk = coefficient of kinetic friction between box and floor = ?
Therefore,
52 N = μk(50 kg)(9.8 m/s²)
μk = (52 N)/(490 N)
μk = 0.106
The coefficient of kinetic friction between the box and the floor will be 0.106.
What is kinetic friction?A force that acts among sliding parts is referred to as kinetic friction. A body moving on the surface is subjected to a force that opposes its progressive motion
The size of the force will be determined by the kinetic friction coefficient between the two materials.
The given data in the problem is;
μ is the coefficient of kinetic friction=?
m is the mass = 50 kg
g is the acceleration due to gravity= 9.81 m/s²
v is the speed =3.5 m/sec
Force(F)= 52 Newton
The formula for kinetic friction force is;
[tex]\rm F= \mu_k R \\\\ R=mg \\\\ F= \mu_k mg \\\\\ 52 = \mu_k \times 50 \times 9.81 \\\\ \mu_k = 0.106[/tex]
Hence,the coefficient of kinetic friction between the box and the floor will be 0.106.
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If you maintain a constant force on an object what happens to the acceleration? What happens to the
velocity?
Answer:
Because you have no force, the acceleration is zero and the body moves at a constant speed
A space shuttle travels around the Earth at a constant speed of 28000 kilometers per hour. If it takes 90 minutes to complete one orbit, how far is its journey around Earth?
Answer Quick plz!
Answer:
Explanation:
14
A battleship simultaneously fires two shells toward two identical enemy ships. One shell hits ship A, which is close by, and the other hits ship B, which is farther away. The two shells are fired at the same speed. Assume that air resistance is negligible and that the magnitude of the acceleration due to gravity is g.1. What shape is the trajectory (graph of y vs. x) of the shells?a. straight lineb. parabolac. hyperbolad. the shape cannot be determined.2. For two shells fired at the same speed which statement about the horizontal distance traveled is correct?A. The shell fired at a larger angle with respect to the horizontal lands farther away.B. The shell fired at an angle closest to 45 degrees lands farther away.C. The shell fired at a smaller angle with respect to the horizontal lands farther away.D. The lighter shell lands farther away.Now, consider for the remaining parts of the question below that both shells are fired at an angle greater than 45 degrees with respect to the horizontal. Remember that enemy ship A is closer than enemy ship B.3. Which shell is fired at the larger angle?A. AB. BC. Both shells are fired at the same angle.4. Which shell is launched with a greater vertical velocity, vy?
A. AB. BC. Both shells are launched with the same vertical velocity.5. Which shell is launched with a greater horizontal velocity, vx?A. AB. BC. Both shells are launched with the same horizontal velocity.6. Which shell reaches the greater maximum height?A. AB. BC. Both shells reach the same maximum height.7. Which shell has the longest travel time (time elapsed between being fired and hitting the enemy ship)?A. AB. BC. Both shells have the same travel time.
Answer:
1) the correct answer is B , 2) θ= 45º,
3) the projectile A must have a greater angle ,
4A) vₓ (B)> vₓ (A) ,
5B) The maximum height is reached by the projectile with the highest speed, from the front this is projectile B
7) if the vertical velocity of both projectiles is the same time is the same
therefore the two projectiles have equal flight times
Explanation:
In this long exercise you are asked to answer a series of questions about the launching of projectiles
1) Path type
since they indicate that the air resistance is negligible the horizontal displacement is
x = v₀ₓ t
On the vertical axis, a relationship acts, which is gravity, therefore its displacement is
y = [tex]v_{oy}[/tex] t - ½ g t²
let's substitute to eliminate time
y = v_{oy} (x / v₀ₓ) - ½ g (x / v₀ₓ)²
y = (tan θ) x - (g / v₀ₓ²) x²
we can see that this is the equation of a parabola
therefore the correct answer is B
2) From the missile launch expressions the range is
R = x = v₀² sin² 2θ / g
for the range to be maximum sin 2θ = 1, this occurs for
2θ = 90
θ= 45º
the correct answer is "The projectile fired at an angle close to 45º lands farther"
In response D implies that the projectile has been divided into two parts, in this case it is true that the lighter part must go further.
3) From the expression of scope we can see that as the angle increases the square sine becomes smaller, for example without 180 = 0
therefore to reach the nearest ship A must launch with a greater angle, therefore the projectile A must have a greater angle
Respect the questions are a bit strange.
* If the projectiles are fired at the same angle and in the statement they indicate that the velocities are equal, the two must reach the same height 4
4A. If the vertical speed is equal, the projectile that must reach the furthest ship (B) must have more horizontal speed
vₓ (B)> vₓ (A)
5B. Both are launched with the same horizontal speed.
which is higher
[tex]v_{y}[/tex]² = v_{oy}² - 2 g y
at maximum height vertical velocity is zero (v_{y} = 0)
0 = v_{oy}² - 2 g y
y = v_{oy}² / 2g
the maximum height is reached by the projectile with the highest speed, from the front this is projectile B
7) they both reach the same height
As the value of the acceleration due to gravity is constant, the time to go up is the same time to go down, therefore if the two projectiles reach the maximum height, the time used is
[tex]v_{y}[/tex] = v_{oy} - g t
0 = v_{oy} - gt
t = v_{oy} / g
if the vertical velocity of both projectiles is the same time is the same
therefore the two projectiles have equal flight times
What is the approximate wavelength of a light whose first-order bright band forms a diffraction angle of 45.0° when it passes through a diffraction grating that has 500.0 lines per mm?
236 nm
353 nm
943 nm
1414 nm
Answer:
D) 1414 nm
Explanation:
This is correct on Edge.
Using the equation dsin(angle)=n(wavelength), we can solve for wavelength.
First we must convert the 500 lines per mm to nm. We do this by 1/500, giving you 0.002. Then move the decimal over six places to the right, resulting in 2000.
Then by plugging in the other values, we have 2000sin(45)=1(wavelength).
N is one because we are just solving for a first-order band.
So 2000sin(45)=wavelength
By using a calculator, we can see that the wavelength equals approximately 1414nm.
I hope this helped. If it did, I would really appreciate a Brainliest!!
Have a great day:)
Answer:
1414
Explanation:
took the test :)
How long does it take to travel a distance of 672km at a speed of 95km/h?
Answer:
7.07 hours
Explanation:
divide the distance by the speed
so in this case, divide 672 by 95
what is work?(theoretically)
Answer:
force×distance
Explanation:
work is the ability of an object to move a distance as a result of the force being applied
Use words from the box to complete the sentences below.
-direction
-energy
-mass
-size
Vectors have size and ___
Scalars have only ____
Answer:
direction
size
Explanation:
Vectors are physical quantities with both magnitude or size and direction.
Scalars are physical quantities with only size but not direction.
Examples of vectors are velocity, displacement and force. Examples of scalar are distance and speedWhen describing a vector, on must specify its magnitude and direction.
Only the size of scalar quantities are needed to describe them.
Two football players are attempting to tackle each other. If one football player has a mass of 100 kg and pushes with a force of 100N onto another football player whose mass is 80kg, how much force does the other player push back with?
Answer:
is it 20kg. Two opposing forces pushing onto each other
An ice skater spins with an angular speed 2w with an angular speed
5.
Assertion (A): Both stretched spring and compressed spring have potential energy
Reason (R): Work is done against the restoring force in each case.
a) Both A and R are true and R is the correct explanation of A
b) Both A and R true and R is not the correct explanation of A
c) A is true but Ris false
d) A is false but R is true
Answer:
A. Both A and R are true and R is the correct explanation of A
Finding volume using displacement and calculating density
Answer:
a) 0.1
b) density = mass/volume
= 0.5 /0.1
= 5 kg/[tex]m^{3}[/tex]
Exit ticket: A lamp is plugged into a 110 Volt electrical outlet. There is a 9 Watt LED bulb in the lamp. a. What is
the current in the bulb? b. What is the resistance of the bulb?
Answer:
(a) 0.081 A (b) 1358.02 ohms
Explanation:
Voltage, V = 110 volt
Power of a LED bulb, P = 9 Watt
(a) Let the current is I. The formula for ower in terms of voltage and power is given by :
P = VI
[tex]I=\dfrac{P}{V}\\\\I=\dfrac{9}{110}\\\\=0.081\ A[/tex]
(b) Let R is the resistance of the bulb. Using Ohm's law as follows :
V = IR
[tex]R=\dfrac{V}{I}\\\\R=\dfrac{110}{0.081}\\\\=1358.02\ \Omega[/tex]
Hence, this is the required solution.
(a) The current in the bulb is 82mA
(b) The resistance of the bulb is 1340 Ω
Given information:
Supply voltage, V = 110V
The power rating of the bulb, P = 9 W
Electrical Power:(a) Current in the bulb:
The electrical power is given by:
P = VI
where V is the voltage, and I is the current
So, I = P/V
I = 9W / 110V = 0.082A
I = 82 mA
(b) Resistance of the bulb:
According to the Ohm's Law:
The relation between voltage (V), current (I), and resistance (R) is given by:
V = IR
110 = 0.082R
R = 1340 Ω
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If object A has more mass than object B, what will object A need to accelerate at the same rate as object B?
Answer:
More force
Explanation:
Object A has more mass than object B
For object A to accelerate at the same rate as object B, it will need more force.
According to Newton's second law of motion "the net force on a body is the product of its mass and acceleration".
Net force = mass x acceleration
Now, if a body has more mass and needs to accelerate at the same rate as another one with a lower mass, the force on it must be increased.
can somone pls help me??!! i’m very stuck
Answer:
its the third one
Explanation:
A resultant force of 4 N acts on a object of mass 0.50 kg for 3 seconds. What is the change in velocity caused by this force?
A- 4 m/s
B- 6 m/s
C- 12 m/s
D- 24 m/s
It’s D but why?
Answer:24
Explanation:
First you need to calculate the acceleration, for this use can use the following formula Force (F) = Mass (M) x Acceleration (A). If we extract A out of this, you can get the following equation A = F/M = 4/0.5 = 8 m/s^2. So, the object accelerates each second by 8 m/s, if the object does this for 3 second, the velocity would be 8 x 3 = 24
Earthquakes are essentially sound waves—called seismic waves—traveling through the earth. Because the earth is solid, it can support both longitudinal and transverse seismic waves. The speed of longitudinal waves, called PP waves, is 8000 m/sm/s. Transverse waves, called SS waves, travel at a slower 4500 m/sm/s. A seismograph records the two waves from a distant earthquake. The SS wave arrives 2.0 minmin after the PP wave. Assume that the waves travel in straight lines, although actual seismic waves follow more complex routes.
Question
Earthquakes are essentially sound waves—called seismic waves—traveling through the earth. Because the earth is solid, it can support both longitudinal and transverse seismic waves. The speed of longitudinal waves, called P waves, is 8000 m/s Transverse waves, called S waves, travel at a slower 4500 m/s. A seismograph records the two waves from a distant earthquake. The S wave arrives 2.0 min after the PP wave.How far away is the Earthquake. Assume that the waves travel in straight lines, although actual seismic waves follow more complex routes.
Answer:
The distance is [tex]d = 1.23 *10^{6} \ m[/tex]
Explanation:
From the question we are told that
The speed of longitudinal seismic wave is [tex]v_p = 8000 \ m/s[/tex]
The speed of Transverse seismic wave is [tex]v_s = 4500 \ m/s[/tex]
The time difference between the arrival of longitudinal seismic with respect to Transverse waves is [tex]\Delta t = 2.0\ min = 120\ seconds[/tex]
Generally the time difference between the arrival of longitudinal seismic with respect to Transverse waves is mathematically represented as
[tex]\Delta t = t_p - t_s[/tex]
=> [tex]\Delta t =\frac{d}{v_p} -\frac{d}{v_s}[/tex]
=> [tex]d = \frac{\Delta t}{ \frac{1}{v_p} - \frac{1}{v_s} }[/tex]
=> [tex]d = \frac{120 }{ \frac{1}{8000} - \frac{1}{4500} }[/tex]
=> [tex]d = 1.23 *10^{6} \ m[/tex]